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3 years ago

Which argument is valid?

1 answer:

8 0

1 - True. If a number is divisible by 12 it's divisible by 6 and thus by 3

2 - False. A rhombus needn't have square angles

3 - False. the second proposition is unrelated to the first one, and doesn't allow us to deduce that cats have fur.

4 - False - We cannot link the first and second proposition in any way to make the third

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PLEASE HELP IM STUCK

Fiesta28 [93]

Answer:

y = 7.25 + 0.65x

Step-by-step explanation:

y = total cost

x = each mile

it starts at 7.25

any mile after that is an extra $0.65

y = 7.25 + 0.65x

8 0

2 years ago

The Buffalo bills are offering autographs signings they charge a supply fee of 8.00 and a player fee of 13.25 per autograph you

Anika [276]

Total to pay per autograph= 8.00+13.25=21.25

Number of autographs you can buy = 2(21.25)= 42.5
You can buy two autographs and have a change of 8.25

6 0

3 years ago

A corporation randomly selects 150 salespeople and finds that 66% who have never taken a self- improvement course would like to

Citrus2011 [14]

Answer:

We conclude that there is no difference in the two population proportions using α = 0.05.

Step-by-step explanation:

We are given that a corporation randomly selects 150 salespeople and finds that 66% who have never taken a self- improvement course would like to do so.

The firm did a similar study 10 years ago and found that 70% of a random sample of 160 salespeople wanted a self-improvement course.

Let $p_1 (\pi_1)$ = true proportion of workers who would like to attend a self-improvement course in the recent study.

$p_2 (\pi_2)$ = true proportion of workers who would like to attend a self-improvement course in the past study.

SO, Null Hypothesis, $H_0$ : $p_1=p_2$ {means that there is no difference in the two population proportions}

Alternate Hypothesis, $H_A$ : $p_1\neq p_2$ {means that there is a difference in the two population proportions}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of salespeople who would like to attend a self-improvement course in recent study = 66%

$\hat p_2$ = sample proportion of salespeople who would like to attend a self-improvement course in past study = 70%

$n_1$ = sample of salespeople in recent study = 150

$n_2$ = sample of salespeople in past study = 160

So, the test statistics = $\frac{(0.66-0.70)-(0)}{\sqrt{\frac{0.66(1-0.66)}{150}+\frac{0.70(1-0.70)}{160} } }$

= -0.755

The value of z test statistics is -0.755.

Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that there is no difference in the two population proportions.

5 0

3 years ago

What is the common multipule of 75 and 1000

Zanzabum

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ I'm assuming you are asking for the lowest common multiple

[if not, let me know]

The answer would be 3000

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

6 0

3 years ago

How do you answer this following equation “ the sum of two numbers is 33 , and the sum of 7 times the first number and 5 times t

nadya68 [22]

$\bf \begin{cases} a\\\\ b \end{cases}\qquad \qquad \begin{array}{llll} \stackrel{\textit{the sum of \underline{a} and \underline{b}}}{a+b=33}\\\\ \stackrel{\textit{the sum of 7 times \underline{a} and 5 times \underline{b}}}{7a+5b=197} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a+b=33\implies \boxed{b}=33-a \\\\\\ \stackrel{\textit{substituting \boxed{b} in the second equation}}{7a+5\left(\boxed{33-a} \right)=197}\implies 7a+165-5a=197$

$\bf 2a+165=197\implies 2a=32\implies a=\cfrac{32}{2}\implies \blacktriangleright a=16 \blacktriangleleft \\\\\\ \boxed{b}=33-a\implies b=33-16\implies \blacktriangleright 17\blacktriangleleft$

4 0

3 years ago