A simple answer is that any given trapezoid with height h and length of the parallel lines a and b, is half of a parallelogram with an area of (a+b) x h. Since the trapezoid is half of this, it is h(a+b)/2
Shaded area = area of the hexagon – area of the pentagon + area of the square – area of the equilateral triangle. This can be obtained by finding each shaded area and then adding them.
<h3>Find the expression for the area of the shaded regions:</h3>
From the question we can say that the Hexagon has three shapes inside it,
Also it is given that,
An equilateral triangle is shown inside a square inside a regular pentagon inside a regular hexagon.
From this we know that equilateral triangle is the smallest, then square, then regular pentagon and then a regular hexagon.
A pentagon is shown inside a regular hexagon.
- Area of first shaded region = Area of the hexagon - Area of pentagon
An equilateral triangle is shown inside a square.
- Area of second shaded region = Area of the square - Area of equilateral triangle
The expression for total shaded region would be written as,
Shaded area = Area of first shaded region + Area of second shaded region
Hence,
⇒ Shaded area = area of the hexagon – area of the pentagon + area of the square – area of the equilateral triangle.
Learn more about area of a shape here:
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Answer:
y = 1/4x + 11/4
Step-by-step explanation:
Given the slope, m = 1/4, and the point, (1, 3):
We can substitute these values into the slope-intercept form, y = mx + b, in order to solve for the y-intercept.
The y-coordinate (b) of the point, (0, <em>b </em>) is the <u>y-intercept </u>of the line where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0.
y = mx + b
3 = 1/4(1) + b
3 = 1/4 + b
Subtract 1/4 from both sides:
3 - 1/4 = 1/4 - 1/4 + b
11/4 = b
The y-coordinate, b, of the y-intercept is 11/4.
Therefore, the slope-intercept form is: y = 1/4x + 11/4
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