Ur answer is 87 bam wham turkey and ham
If all the cheese slices have same mass, say m grams
and mass of 3 cheese slices is 27
so,
m+m+m=27
3m=27
or m=27/3
m=9
thus
mass of one cheese slice is 9 grams
Answer:
1 possibility is there for the the position of the fourth vertex.
Answer:
![N_c \approx 5.0](https://tex.z-dn.net/?f=N_c%20%5Capprox%205.0)
Step-by-step explanation:
From the question we are told that:
Waiting time for a container of the wheels during production ![T_w=0.25day](https://tex.z-dn.net/?f=T_w%3D0.25day)
Average processing time is ![T_a=0.15 day per container](https://tex.z-dn.net/?f=T_a%3D0.15%20day%20per%20container)
Wheel per container ![N_w=200](https://tex.z-dn.net/?f=N_w%3D200)
Total wheel per day ![D=2000](https://tex.z-dn.net/?f=D%3D2000)
Policy variable of
Generally the equation for Total number of container
is mathematically given by
![N_c=DT(\frac{1+X}{N_w} )](https://tex.z-dn.net/?f=N_c%3DDT%28%5Cfrac%7B1%2BX%7D%7BN_w%7D%20%29)
Where
Total time ![T=T_w+T_a](https://tex.z-dn.net/?f=T%3DT_w%2BT_a)
![T=0.15+0.25](https://tex.z-dn.net/?f=T%3D0.15%2B0.25)
Therefore
![N_c=DT(\frac{1+X}{N_w} )](https://tex.z-dn.net/?f=N_c%3DDT%28%5Cfrac%7B1%2BX%7D%7BN_w%7D%20%29)
![N_c=2000*0.40(\frac{1+0.5}{200} )](https://tex.z-dn.net/?f=N_c%3D2000%2A0.40%28%5Cfrac%7B1%2B0.5%7D%7B200%7D%20%29)
![N_c=(\frac{840}{200} )](https://tex.z-dn.net/?f=N_c%3D%28%5Cfrac%7B840%7D%7B200%7D%20%29)
![N_c=4.2](https://tex.z-dn.net/?f=N_c%3D4.2)
![N_c \approx 5.0](https://tex.z-dn.net/?f=N_c%20%5Capprox%205.0)
Therefore the number of Kanban containers needed for the wheels is
![N_c \approx 5.0](https://tex.z-dn.net/?f=N_c%20%5Capprox%205.0)
The Answer is B because the volume is 7*5*14, divide that by 5, 1 fifth = 98, this means 98 times 2 is the volume of white.