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hoa [83]
3 years ago
11

The sides of a triangle are (x+5), and (x+8) units. Find the value of x if the perimeter of the triangle is 106 units.

Mathematics
1 answer:
lutik1710 [3]3 years ago
5 0
106=x+x+5+x+8

106=3x+13

3x=93

x=31

(the sides are 31, 36, 39 respectively)
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Perpendicular to y = 2x – 6<br> and passing through (4,3)
ladessa [460]

Answer:

y = - 1/2x + 5

Step-by-step explanation:

y = 2x – 6        slope = 2

Perpendicular line slope = -1/2

for (4 , 3)      y = mx + b       y = 3, x = 4,   m = -1/2

b = y - mx = 3 - (-1/2) x 4 = 5

equation: y = - 1/2x + 5

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3 years ago
How are real numbers different from irrational number?
Readme [11.4K]
Those labels are not opposites. There are tons of real irrational numbers.
3 0
3 years ago
–x – 7 = 16 please help me
atroni [7]
Move the -7 to the right, its sign will flip (do you know why?)
Negate both sides to change -x to x

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7 0
3 years ago
Read 2 more answers
Brad has eight more nickels than quarters. Altogether he has $6.10. how many of each does he have
wlad13 [49]

Brad have 19 quarters and 27 nickels.

Step-by-step explanation:

Given,

Total worth of nickels and quarters = $6.10 = 6.10*100 = 610 cents

One quarter = 25 cents

One nickel = 5 cents

Let,

x represent the number of quarters.

y represent the number of nickels.

According to given statement;

25x+5y=610     Eqn 1

y = x+8              Eqn 2

Putting value of y from Eqn 1 in Eqn 2

25x+5(x+8)=610\\25x+5x+40=610\\30x=610-40\\30x=570

Dividing both sides by 30

\frac{30x}{30}=\frac{570}{30}\\x=19

Putting x=19 in Eqn 2

y=19+8\\y=27

Brad have 19 quarters and 27 nickels.

Keywords: linear equation, subtraction

Learn more about subtraction at:

  • brainly.com/question/9369548
  • brainly.com/question/9328925

#LearnwithBrainly

7 0
3 years ago
Heights​ (cm) and weights​ (kg) are measured for 100 randomly selected adult​ males, and range from heights of 138 to 190 cm and
mart [117]

Answer:

Best predicted value of y' = 86.16 kg

Step-by-step explanation:

Given,

n = 100

Range of heights = 138 - 190cm

Range of weight = 39 to 150 kg

x' =167.46 cm

y' = 81.44 kg

r = 0.108

p value = 0.285

y = - 105 + 1.08x

Significance level = 0.05

We reject H0 since pvalue, 0.285 is less than significance level of 0.05.

Therefore,

Given height of adult male, x = 177 cm

y = - 105 + 1.08x

The best predicted value of y' =

y' = - 105 + 1.08(177)

y' = 86.16 kg

The best predicted value of y' is 86.16kg

6 0
3 years ago
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