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3 years ago

Given the net with dimensions below, find the surface area of the shape.

Mathematics

1 answer:

Colt1911 [192]3 years ago

8 0

Answer:

136 cm²

Step-by-step explanation:

I'm going to split the net into:

2x 7 cm by 2 cm rectangles

2x 6 cm by 7 cm rectangles

2x 6 cm by 2 cm rectangles

The 2x means there's 2 of them.

Let's find the area of the 2x 7 cm by 2 cm rectangles:

2*7*2=

4*7=

28 cm²

Let's find the area of the 2x 6 cm by 7 cm rectangles:

2*6*7=

2*42=

84 cm²

Let's find the area of the 2x 6 cm by 2 cm rectangles:

2*6*2=

12*2=

24 cm²

Adding all these areas together gives us the surface area of the net:

28+84+24=136 cm²

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xeze [42]

Answer:

47 degrees

Step-by-step explanation:

The sum of angles in a triangle must be 180

32+101+x=180

133+x=180

x=47.

6 0

2 years ago

Can someone help me with question d and e and explain

Bas_tet [7]

D. X cubed
E. X to the negative 3

4 0

3 years ago

For each of these lists of integers, provide a simple formula orrule that generates the terms of an integer sequence that begins

mariarad [96]

Answer:

The next three terms for each are: a) 123, 146, 171; b) 47,51,55; c) 10000,10001, 10010; d)8,8,8; f)654729075,13749310575,316234142225; g)0,0,0

Step-by-step explanation:

In a) the last number +(2i+1) in which i is the number of terms=1,2,3...

b) n+4, for any last number, you add 4

c) 1,0 and the same is repeated for the next decimal

d) n=sum of 2 previous different numbers. The frequency is given by 2i-1 in which is is the number of terms i=1,2,3...

e) missing

f) ni+1=n*(2i-1) in which ni+1 is the resulting number, n is the previous number and i is the number of terms=1,2,3...

g) it is 1 for odd numbers and 0 for even numbers. The frequency is given by i+1, in which the number of terms i= 0,1,2,3...

6 0

3 years ago

Please help me with the circled ones !

TiliK225 [7]

i can only help you with the volume of #5.

So the volume of a cylinder is = πr²h.

First , put the numbers in the equation.

π(6)² (14)

Next you solve.

π(6)²(14) = 36 (14) π = 504π

V= 504π

4 0

3 years ago

Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail inste

Vladimir [108]

Answer:

The value of t test statistics is 5.9028.

We conclude that the true mean is greater than 10 at the .01 level of significance.

Step-by-step explanation:

We are given that a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail instead.

The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample mean of 14.44 with a standard deviation of 4.45 pages.

Let $\mu$ = true mean transmission of pages.

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ 10 pages {means that the true mean is smaller than or equal to 10}

Alternate Hypothesis, $H_A$ : $\mu$ > 10 pages {means that the true mean is greater than 10}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = 14.44 pages

s = sample standard deviation = 4.45 pages

n = sample of fax transmissions = 35

So, test statistics = $\frac{14.44-10}{\frac{4.45}{\sqrt{35} } }$ ~ $t_3_4$

= 5.9028

(a) The value of t test statistics is 5.9028.

Now, at 0.01 significance level the z table gives critical values of 2.441 at 34 degree of freedom for right-tailed test.

Since our test statistics is more than the critical values of z as 5.9028 > 2.441, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the true mean is greater than 10.

(b) Now, P-value of the test statistics is given by the following formula;

P-value = P( $t_3_4$ > 5.9028) = Less than 0.05% {using t table)

7 0

3 years ago