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soldi70 [24.7K]
3 years ago
7

Given the net with dimensions below, find the surface area of the shape.

Mathematics
1 answer:
Colt1911 [192]3 years ago
8 0

Answer:

136 cm²

Step-by-step explanation:

I'm going to split the net into:

2x          7 cm by 2 cm rectangles

2x          6 cm by 7 cm rectangles

2x          6 cm by 2 cm rectangles

The 2x means there's 2 of them.

Let's find the area of the 2x 7 cm by 2 cm rectangles:

2*7*2=

4*7=

28 cm²

Let's find the area of the 2x 6 cm by 7 cm rectangles:

2*6*7=

2*42=

84 cm²

Let's find the area of the 2x 6 cm by 2 cm rectangles:

2*6*2=

12*2=

24 cm²

Adding all these areas together gives us the surface area of the net:

28+84+24=136 cm²

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An exponentially function is expressed in the form y = axb^x . The relation represents a growth when _ and a decay when _ .
Sergio [31]

Answer:

The relation represents a growth when b>1 and a decay when 0<b<1

Step-by-step explanation:

Any function in the form f(x)= a(b^x), where a > 0, b > 0 and b not equal to 1 is called an exponential function with base b. If 0 < b < 1.  It is an example of an exponential decay. The general shape of an exponential with b > 1 is an example of exponential growth. An exponential function is expressed in the form y=a(b^x) The relation represents a growth when  b >1 and a decay when 0<b<1.

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3 years ago
I NEED HELP WITH THESE TWO QUESTIONS PLZ DO NOT ANSWER IF YOU CANNOT EXPLAIN THE ANSWER
Murljashka [212]

9514 1404 393

Answer:

  1. asymptotes: x=-6, x=6, y=0; zero: x=0

  2. 20 blue fish

Step-by-step explanation:

1. The vertical asymptotes are where the denominator is zero. It factors as (x-6)(x+6), so will have zeros at x=-6 and x=6.

The horizontal asymptote is at the limit when x goes to infinity. Here, the ratio of highest-degree terms is 6/x, so the value goes to zero as x gets large.

The zero is where the numerator is zero, at x=0.

In summary:

  • vertical asymptotes: x = ±6
  • horizontal asymptote: y = 0
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__

2. 60% are red, so 40% are blue. The difference in percentages is 60%-40% = 20%. The percentage of blue fish (40%) is twice the difference (=2×20%), so the number of blue fish is twice the difference in numbers.

  blue fish = 2×10 = 20 fish

<em><u>Check</u></em>

There are then 20+10=30 red fish, so 20+30=50 fish total. Reds are 30/50 = 60% of the total.

<u><em>Additional comment</em></u>

I find it often works well to work with ratios, which I can often do in my head. Other folks like to see equations. Here, we could write equations like ...

  r = 60%(r + b) . . . . reds are 60% of the total

  r - b = 10 . . . . . . . . 10 more reds than blues

We want the value of b, so we can eliminate r by substituting for it:

  r = 10 + b . . . . from the second equation above

  (10 +b) = 0.60((10 +b) + b) . . . . substitute for r

  10 +b = 6 + 1.2b . . . simplify

  4 = 0.2b . . . . subtract b+6

  20 = b . . . . . . multiply by 5 (there are 20 blue fish)

6 0
3 years ago
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A triangle has the following side lengths: x - 2, x, and 3x + 1. Another triangle has the following side lengths: 2x - 5, x + 4,
notka56 [123]

we know that

Perimeter of a triangle is equal to

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