The force in the rod when the temperature is 150 °F is 718.72 pounds-force.
<h3>How to determine the resulting the resulting force due to mechanical and thermal deformation</h3>
Let suppose that rod experiments a <em>quasi-static</em> deformation and that both springs have a <em>linear</em> behavior, that is, force (
), in pounds-force, is directly proportional to deformation. Then, the elongation of the rod due to <em>temperature</em> increase creates a <em>spring</em> deformation additional to that associated with <em>mechanical</em> contact.
Given simmetry considerations, we derive an expression for the <em>spring</em> force (), in pounds-force, as a sum of mechanical and thermal effects by principle of superposition:
(1)
Where:
- Spring constant, in pounds-force per inch.
- Spring deformation, in inches.
- Rod elongation, in inches.
The <em>rod</em> elongation is described by the following <em>thermal</em> dilatation formula:
(2)
Where:
- Coefficient of linear expansion, in 
.
- Initial length of the rod, in inches. 
- Initial temperature, in degrees Fahrenheit.
- Final temperature, in degrees Fahrenheit.
If we know 
, 
, 
, 
, 
and 
, then the force in the rod at final temperature is:
![F = \left(1000\,\frac{lb}{in} \right)\cdot \left[0.7\,in + 0.5\cdot\left(6.5\times 10^{-6}\,\frac{1}{^{\circ}F} \right)\cdot (48\,in)\cdot (150\,^{\circ}F-30\,^{\circ}F)\right]](https://tex.z-dn.net/?f=F%20%3D%20%5Cleft%281000%5C%2C%5Cfrac%7Blb%7D%7Bin%7D%20%5Cright%29%5Ccdot%20%5Cleft%5B0.7%5C%2Cin%20%2B%200.5%5Ccdot%5Cleft%286.5%5Ctimes%2010%5E%7B-6%7D%5C%2C%5Cfrac%7B1%7D%7B%5E%7B%5Ccirc%7DF%7D%20%5Cright%29%5Ccdot%20%2848%5C%2Cin%29%5Ccdot%20%28150%5C%2C%5E%7B%5Ccirc%7DF-30%5C%2C%5E%7B%5Ccirc%7DF%29%5Cright%5D)
The force in the rod when the temperature is 150 °F is 718.72 pounds-force. 
To learn more on deformations, we kindly invite to check this verified question: brainly.com/question/13774755
Answer:
The pet sitter babysat his dog for 3 hours.
Step-by-step explanation:
You know that a pet sitter charges $ 20 for supplies and $ 10 per hour of service, represented by the equation C = 10*n + 20, which describes the total cost she would charge for n hours of service.
The pet sitter charges a customer $ 50 for his service, so C has a value of $ 50.
Replacing:
50=10*n+20
Solving:
50 - 20= 10*n +20 -20
30= 10*n
30÷10= n
3= n
<u><em>The pet sitter babysat his dog for 3 hours.</em></u>
Answer:
Step-by-step explanation:
Answer:
$98.82
Step-by-step explanation:
Given data
A pair of shoes cost $52 and a dress was $70 at Belk
Total expenses
= 52+70
= $122
coupon = 25%
=25/100* 122
=0.25*122
= $30.5
Tax= 6%
= 6/100*122
= 0.06*122
= $7.32
Hence the total is
= 122-30.5+7.32
= 91.5+7.32
= $98.82
