Please answer quickly and with the write answer.

Solve this problem in your notebook using all four steps. Harvey is 3 times as old as Jane. The sum of their ages is 48 years. F

kaheart [24]

By saying jane is 1/3 of harvey then J=1/3 H
by removing J and adding the new quantity we git u will got the answer

3 0

3 years ago

Read 2 more answers

6(x+2)+7=5(x+3)-7(x-2)

saul85 [17]

Answer:

10/8 or 1 1/5

Step-by-step explanation:

1) distributive property

6(x+2)+7=5(x+3)-7(x-2)
6x+12+7=5x+15-7x+14

2) combine like terms

6x+19=-2x+29
8x=10

3) isolate x

divide both sides by 8

4)simplify

10/8 --> 1 1/5

8 0

3 years ago

Read 2 more answers

Eric made two investments:

klemol [59]

Answer:10

Step-by-step explanation:

Notice that investment Q’s value grows linearly while investment R’s value grows exponentially. In conclusion, investment R’s value will first exceed investment Q’s value in year number 10

3 0

3 years ago

Read 2 more answers

Angle α lies in quadrant II , and tanα=−125 . Angle β lies in quadrant IV , and cosβ=35 .

Artist 52 [7]

Answer:

$cos(\alpha+\beta)=\frac{33}{65}$

Step-by-step explanation:

step 1

Find cos α

we know that

$tan^2(\alpha)+1=sec^2(\alpha)$

we have

$tan(\alpha)=-\frac{12}{5}$

substitute

$(-\frac{12}{5})^2+1=sec^2(\alpha)$

$sec^2(\alpha)=\frac{144}{25}+1$

$sec^2(\alpha)=\frac{169}{25}$

$sec(\alpha)=\pm\frac{13}{5}$

Remember that Angle α lies in quadrant II

so

sec α is negative

$sec(\alpha)=-\frac{13}{5}$

Find the value of cos α

$cos)\alpha)=\frac{1}{sec(\alpha)}$

so

$cos(\alpha)=-\frac{5}{13}$

step 2

Find sin α

we know that

$tan(\alpha)=\frac{sin(\alpha)}{cos(\alpha)}$

$sin(\alpha)=tan(\alpha)cos(\alpha)$

we have

$tan(\alpha)=-\frac{12}{5}$

$cos(\alpha)=-\frac{5}{13}$

substitute

$sin(\alpha)=(-\frac{12}{5})(-\frac{5}{13})$

$sin(\alpha)=\frac{12}{13}$

step 3

Find sin β

we know that

$sin^2(\beta)+cos^2(\beta)=1$

we have

$cos(\beta)=\frac{3}{5}$

substitute

$sin^2(\beta)+(\frac{3}{5})^2=1$

$sin^2(\beta)=1-(\frac{3}{5})^2$

$sin^2(\beta)=1-\frac{9}{25}$

$sin^2(\beta)=\frac{16}{25}$

$sin(\beta)=\pm\frac{4}{5}$

Remember that

Angle β lies in quadrant IV

so

sin β is negative

$sin(\beta)=-\frac{4}{5}$

step 4

Find cos(α−β)

we know that

$cos(\alpha+\beta)=cos(\alpha)cos(\beta)-sin(\alpha)sin(\beta)$

we have

$cos(\alpha)=-\frac{5}{13}$

$cos(\beta)=\frac{3}{5}$

$sin(\alpha)=\frac{12}{13}$

$sin(\beta)=-\frac{4}{5}$

substitute the given values

$cos(\alpha+\beta)=(-\frac{5}{13})(\frac{3}{5})-(\frac{12}{13})(-\frac{4}{5})$

$cos(\alpha+\beta)=(-\frac{15}{65})+(\frac{48}{65})$

$cos(\alpha+\beta)=\frac{33}{65}$

7 0

4 years ago

Answer for these! Please quickly

hram777 [196]

Answer:

1: 233 (E)

2: 10,920 (C)

3: 241.87 (F)

4: 12600 (B)

Step-by-step explanation:

Use the Pythagorean Theorem to find the hypotenuse (the missing side length):

$a^{2} + b^{2} = c^{2} \\c = \sqrt{a^{2} + b^{2}}$

To find area of triangle:

A = 1/2 • base • height

5 0

2 years ago