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3 years ago

Find the distance between the points (2,8) and (-1,9)

Mathematics

1 answer:

Sphinxa [80]3 years ago

7 0

Use the distance formula: D=sqrt((x2-x1)^2+(y2-y1)^2)

Plug in:

D=sqrt((9-8)^2+(-1-2)^2)

D=sqrt(1^2+(-3)^2)

D=sqrt(1+9)

D=sqrt(10)

So the distance is about 3.16 units

Hope this helped!

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Solve the equation. 2x - 8(x+1)= 6(2x - 3)

Flura [38]

ANSWER
$x = \frac{5}{9}$

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3 years ago

Thirty students at Eastside High School took the SAT on the same Saturday. Their raw scores are given next. 1,450 1,620 1,800 1,

IRISSAK [1]

Answer:

Number of students who scored atleast 1700 but less Than 2100 = 17

Step-by-step explanation:

Given the data :

1,450 1,620 1,800 1,740 1,650 1,800 2,010 1,780 1,840 1,490 1,620 1,480 2,390 1,640 1,830 1,710 1,900 1,910 1,950 1,820 1,590 2,350 2,260 1,870 1,530 1,950 2,000 1,830 1,980 2,100

Class interval __ Frequency

1400 - 1599 ____ 5

1600 - 1799 ____ 7

1800 - 1999 ____12

2000 - 2199 ___ 3

2200 - 2399 ___ 3

Number of students who scored atleast 1700 but less Than 2100 = 17

8 0

3 years ago

Simplify the expression by combining like terms. 16+8a−3a+6b−9

Svetradugi [14.3K]

7+5a+6b is the answer because 16-9 is 7 and 8-3 is 5.

4 0

3 years ago

Read 2 more answers

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

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4 years ago

What is the y-intercept of the line?

Fynjy0 [20]

Answer:

The Y-intercept is 1

It is where the line meets the y-axis

~PumpkinSpice1

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3 years ago