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3 years ago

12

You want to put $4,000 in a simple interest account. It has a 2.5% annual interest rate. How long will it take you to earn $500

in interest?

1 answer:

SVEN [57.7K]3 years ago

8 0

Answer:

5 years

Step-by-step explanation:

use the I = Prt simple interest formula

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Y= 16t (squared) +120 what is t

Zina [86]

Answer:

Step-by-step explanation:

hello :

16t²+120 = y

16t² = y -120 so : t² = (y-120)/16

if : y-120 ≥ 0 t = ±√((y-120)/16)

5 0

4 years ago

The slope of 4 and line passes through the point (-3, 1)

Irina-Kira [14]

Go up on the graph (y axis) and you need to go down 3 on the y axis and go to the right one and repeat. let me know if you want me to draw it out!

6 0

3 years ago

Simplify 3^2/3.3^1/5

san4es73 [151]

ANSWER:

$\frac{1}{5} \\$

EXPLANATION:

$\frac{ \frac{{3}^{2}}{3 \times{3}^{1}}}{5} = \\$

$\frac{ \frac{9}{3 \times 3} }{5} = \\$

$\frac{ \frac{9}{9} }{5} = \\$

$\frac{1}{5} \\$

4 0

3 years ago

Two lines, C and D, are represented by the equations given below:

lakkis [162]

y=x+14 line 1

y=3x+2 line 2

These are both the equation of lines written in slope intercept form

y=mx+b where m is the slope and the point (0,b) is the y intercept.

The first line has a slope of m=1. The 2nd line has a slope of m=3

Since these lines have different slopes, they are not parallel, thus they will cross at some point. What you have to determine is where the lines cross, which will be a point (x,y) that is on both lines.

We already have y solved in terms of x from either equation so we can use substitution to solve the system.

Since y=x+14 from line 1, put x+14 in place of y in the equation of line 2.

x+14=3x+2

solve for x.

Subtract x from both sides...

14= 3x-x+2

14=2x+2

subtract 2 from both sides

14-2=2x

12=2x

divide both sides by 2

6=x

We now have the x value of the common point. Plug the value 6 in for x in one of the original equations and solve for y.

y=6+14

y=20

These two lines cross at the point (6,20) which is a point the two lines have in common.

Hope I helped (SharkieOwO)

3 0

3 years ago

Ex 7) Imagine a mile-long bar of metal such as the rail along railroad tracks. Suppose that the rail is anchored on both ends an

Fantom [35]

9514 1404 393

Answer:

about 44.5 feet

Step-by-step explanation:

We can write relations for the height of the rail as a function of initial length and expanded length, but the solution cannot be found algebraically. A graphical solution or iterative solution is possible.

Referring to the figure in the second attachment, we can write a relation between the angle value α and the height of the circular arc as ...

h = c·tan(α) . . . . . . where c = half the initial rail length

Then the length of the expanded rail is ...

s = r(2α) = (c/sin(2α)(2α) . . . . . . where s = half the expanded rail length

Rearranging this last equation, we have ...

sin(2α)/(2α) = c/s

It is this equation that must be solved iteratively. We find the solution to be ...

α ≈ 0.0168538794049 radians

So, the height of the circular arc is ...

h = 2640.5·tan(0.0168538794049) ≈ 44.4984550191 . . . feet

The rail will bow upward by about 44.5 feet.

_____

<em>Additional comments</em>

Note that s and c in the diagram are half the lengths of the arc and the chord, respectively. The ratio of half-lengths is the same as the ratio of full lengths: c/s = 2640/2640.5 = 5280/5281.

We don't know the precise shape the arc will take, but we suspect is is not a circular arc. It seems likely to be a catenary, or something similar.

__

We used Newton's method iteration to refine the estimate of the angle from that shown on the graph. The iterator used is x' = x -f(x)/f'(x), where x' is the next guess based on the previous guess of x. Only a few iterations are required obtain an angle value to full calculator precision.

3 0

3 years ago