Answer:
$4.99
Step-by-step explanation:
20-5.03=14.97
14.97/3=4.99
<span>At least one bear was sighted on 28 separate days in 40 day period total = 28/40
We're looking for the daily frequency of bear sightings, that's in the whole 40 day period.
Let's say 40 days period = 100%.
Then what's 28 days?
</span>
So the solution we're looking for would be (<span><span>28 days∗100) / </span>40 days = 70%</span>
The final answer is B. 70%.
<span>
</span>
Cube surface area = side^2 * 6
54 / 6 = side^2
side = sq root (9)
side = 3 centimeters
//5^-3 = 1/(5^3)
(2^2*5^6)/(5^3*2^3*5^2)=
(2^2*2^-3)*(5^6*5^-3*5^-2)=
(2^-1)*(5^1)=
5/2=
2.5=
Answer:
Q = 3.2
Step-by-step explanation:
So basically you would first re-order the equation. 6.4 + Q = 9.6
Then after that you will move all the terms containing Q to the left and the rest of them on the right. After that you will -6.4 to both sides of the equation. Which will look like this.
6.4 + (-6.4) + Q = 9.6 + (-6.4)
Then you will combine the like terms.
6.4 + (-6.4) = 0.0
0.0 + Q = 9.6 + (-6.4)
<u>Q = 3.2</u>