1)volume of the pipeline
The pipeline is a cylinder, therefore;
Volume (cylinder)=πr²h
r=radius
h=height of the cylinder
diameter=6 in*(1 ft / 12 in)=0.5 ft
raius=diameter / 2=0.5 ft / 2=0.25 ft.
height=5280 ft
Volume (pipeline)=π(0.25 ft)²(5280 ft)=330π ft³≈1036.73 ft³.
2) we calculate the number of barrel
1 mile of oil in this pipeline is 330π ft³ of oil.
1 barrel of crude------------------5.61 ft³
x----------------------------------330π ft³
x=(1 barrel*330π ft³) / 5.61 ft³=184.8 barrels
3) we calculate the price.
1 barrel---------------$100
184.8 barrels---------- x
x=(184.8 barrels * $100) / 1 barrel=$18,480
Solution: ≈$18,480
Answer:
y = x + 5
Step-by-step explanation:
The y values are 5 more than the x values.
Answer:
KL does not name the same line.
Step-by-step explanation:
You'll recognize that if you go from KM, it stays on the same. You go from MN it stays on the same line. KN also stays on the same line. By K and L are two completely different lines. L can only be with N or J
Answer:
Circumference = diameter × π
Take π =3. 14
2x^2y(y^3-5)+14(y^3-5)
(2x^2y)+14(y^3-5)
2(x^2y+7)(y^3-5)
x^2y+7 Is a factor
