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3 years ago

7

jenny had some candy to give to her three children she first took nine pieces for herself and then evenly divided the rest among

her children. Each child recived three pieces with how many pieces did she start

1 answer:

Airida [17]3 years ago

3 0

Answer:18

Step-by-step explanation: She gave 3 children 3 pieces each. 3*3=9. She also took 9 pieces for herself. 9+9=18

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Help please with explain so for further questions like this

Yakvenalex [24]

Rmember (a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)this is just alot of busy work

find f+g first then find f-g

f+g=(x-4)/(x+9)+(x-9)/(x+4)
make denomenator the same
multiply left one by (x+4)/(x+4) and right one by (x+9)/(x+9)
[(x-4)(x+4)]/[(x+9)(x+4)]+[(x-9)(x+9)]/[(x+9)(x+4)]
[x²-16]/[(x+9)(x+4)]+[x²-81]/[(x+9)(x+4)]
[x²+x²-16-81]/[(x+9)(x+4)]
[2x²-97]/[(x+9)(x+4)]

now f-g
[x²-16]/[(x+9)(x+4)]-[x²-81]/[(x+9)(x+4)]
[x²-x²-16+81]/[(x+9)(x+4)]
[65]/[(x+9)(x+4)]

now we got
$\frac{ \frac{2x^2-97}{(x+9)(x+4)} }{ \frac{65}{(x+9)(x+4)} }$
invert and multiply
$(\frac{2x^2-97}{(x+9)(x+4)})(\frac{(x+9)(x+4)}{65})$
$\frac{2x^2-97}{65}$

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