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likoan [24]
3 years ago
13

Jallouk Corporation has two different bonds currently outstanding. Bond M has a face value of $50,000 and matures in 20 years. T

he bond makes no payments for the first six years, then pays $2,100 every six months over the subsequent eight years, and finally pays $2,400 every six months over the last six years. Bond N also has a face value of $50,000 and a maturity of 20 years; it makes no coupon payments over the life of the bond. The required return on both these bonds is 10 percent compounded semiannually. What is the current price of Bond M and Bond N? (Do not round intermediate calculations and round your answers to 2 decimal places, e.g., 32.16.)
Business
1 answer:
Nina [5.8K]3 years ago
4 0

Answer

Current Price of Bond M = $25,202

Current Price of Bond N = $7,102

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

Download xlsx
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Ilia_Sergeevich [38]
Humanidocious is not an actual word because it is not on dictionaries or word that is being used with the definition it contains as this word is a made up or not a real word because this has been used in means of making a made up or fake word in replacing or trying to define something where in the word does not actually exist.
8 0
3 years ago
Olivia bought a $1,874 sprinkler system with her credit card. Her credit card has an APR of 10.31%, compounded monthly. She made
Radda [10]

Answer:

Percentage of the total lifetime cost of the system that the original price made up = 59.07%

Explanation:

The monthly payments for the sprinkler system can be calculated using the formula for calculating the present value of an ordinary annuity as follows:

PV = P * ((1 - (1 / (1 + r))^n) / r) …………………………………. (1)

Where;

PV = Present value or original price of the sprinkler = $1,874

P = Monthly payment = ?

r = Monthly interest rate = APR / 12 = 10.31% / 12 = 0.1031 / 12 = 0.00859166666666667

n = number of months = number of years of payment * 12 = 4 * 12 = 48

Substitute the values into equation (1) and solve P, we have:

$1,874 = P * ((1 - (1 / (1 + 0.00859166666666667))^48) / 0.00859166666666667)

$1,874 = P * 39.1976732321759

P = $1,874 / 39.1976732321759

P = $47.81

Therefore, we have:

Total payment for the sprinkler = Monthly payments * Number of months = P * n = $47.81 * 48 = $2,294.88

Total cost in water = Cost in water per week * Number of weeks in a year * Number of years that Olivia kept the sprinkler system = $2.11 * 52 * 8 = $877.76

Total lifetime cost of the system = Total payment for the sprinkler + Total cost in water = $2,294.88 + $877.76 = $3,172.64

Percentage of the total lifetime cost of the system that the original price made up = (Original price of the sprinkler / Total lifetime cost of the system) * 100 = ($1,874 / $3,172.64) * 100 = 59.07%

4 0
3 years ago
The hardest part about finding work is _____.
Snezhnost [94]
Hey there,

Getting the first job would probably be the hardest. So the answer is C.

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6 0
3 years ago
Read 2 more answers
Harvey, a u.s. taxpayer, purchased 10 shares of mvc stock for $100 per share; one year later he sold the 10 shares for $130 a sh
Nonamiya [84]
<span>Harvey purchased 10 shares of mvc stock for = $100 per share
</span><span>one year later he sold the 10 shares for = $130 a share
</span>The price level increased in a year from = 140 to 147
<span>harvey's before-tax real capital gain =
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5 0
3 years ago
Keesha Co. borrows $230,000 cash on December 1 of the current year by signing a 150-day, 12%, $230,000 note. 1. On what date doe
muminat

Answer:

See explanation section

Explanation:

Requirement 1

April 30 is the maturity date of the note.

December 31 + January 31 + February 28 + March 31 + April 30 = 150 days.

Therefore, the note will be matured in the April 30, next year.

Requirement 2 & 3

Current year Interest: December 1 - December 31 = 30 days interest = $230,000 × 12% × (30 ÷ 360) = $2,300.

Following year Interest: January 1 - April 30 = 120 days interest = $230,000 × 12% × (120 ÷ 360) = $9,200.

Total Interest = $11,500

Requirement 4

Journal Entries

(a)  Dec. 1     Cash                     Debit      $230,000

                    Notes payable     Credit     $230,000

To record the borrow a loan by issuing a 150-day, 12% note.

(b)  Dec. 31   Interest Expense     Debit    $2,300

                    Interest payable      Credit   $2,300

To record the accrued interest expense on December 31 (Current year).

(c)  April 30  Notes payable      Debit     $230,000

                    Interest payable    Debit     $2,300

                    Interest Expense   Debit     $9,200

                                   Cash        Credit       $241,500

To record the payment of the note at maturity.

6 0
3 years ago
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