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3 years ago

Hey can you please help me posted picture of question

Mathematics

2 answers:

ruslelena [56]3 years ago

8 0

Yes he’s right it’s positive infinity so it’s C

xenn [34]3 years ago

4 0

The discriminant can be determined from the number of roots of the graph.

If Disc> 0, the function has two distinct roots
If Disc = 0, the function has a repeated root
If Disc < 0, the function has no real root.

Since, the given function has two distinct roots i.e. it cross x-axes at two different points, its discriminant will be positive.

So, the answer to this question is option C<span />

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Is a pair of adjacent supplementary angles forms a right angle yes or no and why

finlep [7]

Yes because if they are the same size and they are about 45 degrees and at the same corner than yes they can

3 0

3 years ago

Hi<br><br> 1-5 already done!!!!!!!!!!

Scilla [17]

Answer:

According to tangents secant segments theorem,

11) x(16+x) = (x + 6)^2

x (16+x) = (x + 6)^2

16x + x^2 = x^2 + 2(6)(x) + 6^2

16x + x^2 = x^2 + 12x + 36

16x - 12x + x^2 - x^2 = 36

4x = 36

x = 36/4

x = 4

13) x(x + 5) = (x + 2)^2

x^2 + 5x = x^2 + 2x 2(2)(x) + 2^2

x^2 + 5x = x^2 + 4x + 4

x^2 -x^2 + 5x - 4x = 4

x = 4

14) x + 8( x + 8 + 32) = (3x) ^2

x + 8(x + 40) = 9x^2

x(x + 8) + 40(x + 8) = 9x^2

x^2 + 8x + 40x + 320 = 9x^2

x^2 + 48x + 320 =9x^2

48x + 320 = 9x^2 - x^2

48x + 320 = 8x^2

Dividing the whole eq. by 8,

6x = 40 = x^2

0 = x^2 - 6x - 40

0 = x^2 - 10x + 4x - 40

0 = x(x - 10) + 4(x - 10)

x - 10 = 0 OR x + 4 = 0

x = 10 OR x = - 4

length cannot be negative, so,

x = 10

15) (x + 3) ( x + 3 + 15) = (2x) ^2

(x + 3) (x + 18) = 4x^2

x(x + 18) + 3(x + 18) = 4x^2

x^2 + 18x + 3x + 54 = 4x^2

x^2 + 21x + 54 = 4x^2

0 = 4x^2 - x^2 - 21x - 54

0 = 3x^2 - 21x - 54

Dividing the whole eq. by 3,

x^2 - 7x - 18 = 0

x^2 - 9x + 2x - 18 = 0

x(x - 9) + 2 (x - 9)

x + 2 = 0 Or x - 9 = 0

x = -2 or x = 9

length cannot be negative,so,

x = 9

3 0

3 years ago

How does replacing f(x) with f(x) + k, k f(x), f(kx), and f(x + k) for specific values of k (both positive and negative) affect

ivann1987 [24]

F(x) + k - Moves the graph k units up.

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f (kx) stretches the graph by a factor 1/k parallel to x-axis

f(x + k) moves the graph 3 units to the left.

For k negative the first one moves it k units down

for second transform negative does same transfoormation but also reflects the graph in the x axis

For the third transform negative k :- same as above but also reflects in y axis

4th transform - negative k moves graph k units to the right

4 0

3 years ago

Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.

NISA [10]

Answer:

$\frac{\sqrt{\pi}}{4}$