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3 years ago

If p(x) = 2x2 – 4x and q(x) = x – 3, what is (p*q) (x)

1 answer:

6 0

Hello:
(poq)(x) = p(q(x))= p(x-3) = 2(x-3)²-4(x-3) = 2(x²-6x+9)-4(x-3)
(poq)(x) = 2x²-12x+18-4x+12
(poq)(x) = 2x²-16x+30... (answer : C )

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2) (a^3-2a)-(3a^2-4a^3

mylen [45]

Answer:

a x (a2-2)

Step-by-step explanation:

the 2 is supposed to be above the a I don't know how to that while typing.

5 0

3 years ago

Four less than five times a number is equal to 11

SVETLANKA909090 [29]

5*3=15
15-4= 11
hope I helped:)

7 0

3 years ago

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

3 years ago

Frances can complete 91oil changes in 7 days. How many oil changes can Frances complete in 11days? oil changes

Natali [406]

Answer:

143

Step-by-step explanation:

lets make a fraction:

91 oil changes/7days

lets take "x" as the unknown # of oil changes:

x/11

91/7=x/11

we can cross multiply:

91*11=7*x

1001=7x

143=x

so 143 oil changes in 11 days

Hope this helps!

4 0

3 years ago

Read 2 more answers

Round 919827 to the nearst thousand

blondinia [14]

It would be 0 because 8 is over 5 so ya

5 0

3 years ago

Read 2 more answers