Question

Assuming there are 100 million households in the US, and that each household has two HDTVs, and that each TV is used to watch 4 hours of video per day. We’ll assume that each (compressed) video streams at 2Mb/s. If all households are watching both TVs at the same time, and all are watching video on-demand (i.e. data is delivered unicast to every household), then which of the following is the closest approximation of the total peak aggregate data rate delivered to all homes?
100 Tb/s (100 × 10^12b/s),
400 Tb/s (400 x 10^12b/s),
1 Pb/s (1 x 10^15b/s),
100 Gb/s (100 x 10^9 b/s),
2 Tb/s (2 x 10^12b/s)

Answer 1

Answer:

400 Tb/s (400 ×  10¹² b/s )

Explanation:

Given that :

the number of household in US = 100 million

the number of HDTVs per house is = 2

the rate of the video streaming = 2 Mb/s

the watch hour = 4 hours of video per day

We equally know that :

I Mb = 10⁶ bits

The Total peak aggregate data rate delivered to all homes provided every household is watching both the tvs simultaneously =  Total bits streamed × number of households × number of HDTVs

= (100 ×  10⁶)×2 (2× 10⁶) b/s

= 400 ×  10¹² b/s

= 400 Tb/s (400 ×  10¹² b/s )