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creativ13 [48]
3 years ago
15

Assuming there are 100 million households in the US, and that each household has two HDTVs, and that each TV is used to watch 4

hours of video per day. We’ll assume that each (compressed) video streams at 2Mb/s. If all households are watching both TVs at the same time, and all are watching video on-demand (i.e. data is delivered unicast to every household), then which of the following is the closest approximation of the total peak aggregate data rate delivered to all homes?
100 Tb/s (100 × 10^12b/s),
400 Tb/s (400 x 10^12b/s),
1 Pb/s (1 x 10^15b/s),
100 Gb/s (100 x 10^9 b/s),
2 Tb/s (2 x 10^12b/s)
Computers and Technology
1 answer:
BartSMP [9]3 years ago
3 0

Answer:

400 Tb/s (400 ×  10¹² b/s )

Explanation:

Given that :

the number of household in US = 100 million

the number of HDTVs per house is = 2

the rate of the video streaming = 2 Mb/s

the watch hour = 4 hours of video per day

We equally know that :

I Mb = 10⁶ bits

The Total peak aggregate data rate delivered to all homes provided every household is watching both the tvs simultaneously =  Total bits streamed × number of households × number of HDTVs

= (100 ×  10⁶)×2 (2× 10⁶) b/s

= 400 ×  10¹² b/s

= 400 Tb/s (400 ×  10¹² b/s )

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LekaFEV [45]

Explanation:

Answer to the following iterations are:

a)

In the following for-loop, the loop will starts from 0 and end at 9.

for example:

0 1 2 3 4 5 6 7 8 9

So, the loop will iterate 0-9, which means 10 times.

b)

In the following for-loop, the loop will starts from 0 and end at 8 but in the gap of 2 because of the increment of 2 in the variable "i".

for example:

0 2 4 6 8

So, the loop will iterate even times or 5 times, which means 0 2 4 6 8.

c)

In the following for-loop, the loop will starts from 0 and end at 9 but in the gap of 3  because of the increment of 3 in the variable "i" and the value is assign in the variable "incr" is 3.

for example:

0 3 6 9

So, the loop will iterate 4 times, which means 0 3 6 9.

d)

In the following for-loop, the loop will starts from 3 and end at 9 but in the gap of 3  because of the increment of 3 in the variable "i" and the value is assign in the variable "incr" is 3.

for example:

3 6 9

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e)

In the following for-loop, the loop will starts from 10 and end at 1 which means reverse order.

for example:

10 9 8 7 6 5 4 3 2 1

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f)

In the following for-loop, the loop will not works because of the condition which is i is less than 0 but in the following code loop will starts from 3.

So, that's why loop will not iterate.

g)

In the following for-loop, the loop will starts from 1 and end at 9 but in the multiple of 3  because the variable "i" will multiply by the variable "incr" and the value is assign in the variable "incr" is 3.

for example:

1 3 9

So, the loop will iterate 3 times, which means 1 3 9.

h)

In the following for-loop, the loop is the infinite loop because of the condition which is i is less than max but and the loop will starts from 0 and goes on infinite times.

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Opposite word of reassembling​
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3 years ago
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Write a loop to print 10 to 90 inclusive (this means it should include both the
Semmy [17]

Answer:

The loop in cpp language is as follows.

for(int n=10; n<=90; n++)

{

cout<<n<<" ";

count = count+1;

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{

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count=0;

}

}

Explanation:

1. The expected output is obtained using for loop.

2. The loop variable, n is initialized to the starting value of 10.

3. The variable n is incremented by 1 at a time, until n reaches the final value of 90.

4. Every value of n beginning from 10 is displayed folllowed by a space.

5. When 10 numbers are printed, a new line is inserted so that every line shows only 10 numbers.

6. This is achieved by using an integer variable, count.

7. The variable count is initialized to 0.

8. After every number is displayed, count is incremented by 1.

9. When the value of count reaches 10, a new line is inserted and the variable count is initialized to 0 again. This is done inside if statement.

10. The program using the above loop is shown below along with the output.

PROGRAM

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

   int count=0;

   for(int n=10; n<=90; n++)

   {

       cout<<n<<" ";

       count = count+1;

       if(count==10)

       {

           cout<<""<<endl;

           count=0;

       }

       

   }

   return 0;

}  

OUTPUT

10 11 12 13 14 15 16 17 18 19  

20 21 22 23 24 25 26 27 28 29  

30 31 32 33 34 35 36 37 38 39  

40 41 42 43 44 45 46 47 48 49  

50 51 52 53 54 55 56 57 58 59  

60 61 62 63 64 65 66 67 68 69  

70 71 72 73 74 75 76 77 78 79  

80 81 82 83 84 85 86 87 88 89  

90

1. In the above program, the variable count is initialized inside main() but outside for loop.

2. The program ends with a return statement since main() has return type of integer.

3. In cpp language, use of class is not mandatory.

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<h3>What is meant by mesh topology?</h3>

Mesh topology is a kind of networking that is said to be where the full nodes do act in a form of a cooperation  so that they can be able to share or distribute data among themselves.

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