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Anettt [7]
3 years ago
12

What is the differences between 2^8 and 8^2?​

Mathematics
2 answers:
Fynjy0 [20]3 years ago
7 0

Answer:

The answer is 192

Step-by-step explanation:

2^8 = 256

8^2 = 64

256 - 64 = 192

Remember:

2^8 is really 2*2*2*2*2*2*2*2

Remember:

8^2 is really 8*8

To find the <u>difference,</u> you must subtract the smaller product from the larger product.

<Hope this helps!>

dsp733 years ago
4 0

Answer:

192

Step-by-step explanation:

Method 1:

2^8 - 8^2 = 2^8 - 2^6 = 2^6(2^2 - 1) = 64(3) = 192

Method 2:

2^8 - 8^2 = 256 - 64 = 192

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The ordered pairs for :

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(b) Y = 1/x are (-2.-1/2), (5,1/5), (2/3,3/2) and (0.75,1.33)

We are given two functions for which corresponding y-values need to be found for the given x-values so that ordered pairs of the form (x, y) can be formed.

Consider the function Y = 9-4x.

When x = -2, y = 9-(4 x -2) = 17

When x = 5, y = 9-(4 x 5) = -11

When x = 2/3, y = 9-(4 x 2/3) = 9-(8/3) = 19/3

When x = 0.75, y = 9-(4 x 0.75) = 6

So the ordered pairs are: (-2,17), (5,-11) ,(2/3,19/3) and (0.75,6).

Consider the function Y = 1/x

When x = -2, y = 1/-2 = -1/2

When x = 5, y = 1/5

When x = 2/3, y = 1/(2/3) = 3/2

When x = 0.75, y = 1/0.75 = 1.33

So the ordered pairs are: (-2.-1/2), (5,1/5), (2/3,3/2) and (0.75,1.33)

Learn more about ordered pairs at brainly.com/question/20348140

#SPJ9

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Please help me, due soon ​
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Step-by-step explanation:

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