Answer:
1) 22.5 A
2) 112 B
3) 430 L
4) 576 P
5) 486 L
6) 624 S
Code is A B L P L S
Step-by-step explanation:
1) Area of a triangle = 1/2 * base * height = 1/2 *5*9 = 22.5
2) Area of a parallelogram = base x height = 14 x 8 = 112
3) Area of a rectangular prism = 2(length * width) + 2*(length + height) + 2 *(length *height)
= 2(15x7 + 15*5 + 7*5)
= 2(105 + 75 + 35)
= 2 * 215
= 430
4) Volume of a triangular prism = 1/2 * base * length * height
= 1/2 * 8 * 16 * 9
= 576
5) A cube has six surfaces. Each surface has an area of s x s where s is the length of each side. In this case, each side has area of 9x9 = 81. Total surface area = 6 x 81 = 486 and that is the paper required
6) The trailer is a rectangular prism so its volume = length x width x height = 13 6 x 8 = 624
Now you have to look at each value and see which letter it corresponds to. For example answer 1) is 22.5 which lies between 0-100 so it gets letter A, answer (2) is 112 which lies in the range 101-200 so it gets the letter B and so on
In general, a solution of a system in two variables is an ordered pair that makes BOTH equations true. In other words, it is where the two graphs intersect, what they have in common. So if an ordered pair is a solution to one equation, but not the other, then it is NOT a solution to the system
Answer:
h = 10sin(π15t)+35
Step-by-step explanation:
The height of the blade as a function f time can be written in the following way:
h = Asin(xt) + B, where:
B represets the initial height of the blade above the ground.
A represents the amplitud of length of the blade.
x represents the period.
The initial height is 35 ft, therefore, B = 35ft.
The amplotud of lenth of the blade is 10ft, therefore A = 10.
The period is two rotations every minute, therefore the period should be 60/4 = 15. Then x = 15π
Finally the equation that can be used to model h is:
h = 10sin(π15t)+35
Answer:
Step-by-step explanation:
Simplify expression with rational exponents can look like a huge thing when you first see them with those fractions sitting up there in the exponent but let's remember our properties for dealing with exponents. We can apply those with fractions as well.
Examples
(a)
From above, we have a power to a power, so, we can think of multiplying the exponents.
i.e.
Let's recall that when we are dealing with exponents that are fractions, we can simplify them just like normal fractions.
SO;
Let's take a look at another example
Here, we apply the to both 27 and
Let us recall that in the rational exponent, the denominator is the root and the numerator is the exponent of such a particular number.
∴
The answer is the third one