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Sindrei [870]
3 years ago
8

What is the common ratio of the geometric sequence: -1/12, -1/2,-3,-18...?

Mathematics
1 answer:
makvit [3.9K]3 years ago
4 0
The answer is B 1/6 just divide the first number by the second one<span />
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Simplify 14/70<br>please show work
Mumz [18]

Cancel the common factors in the numerator and denominator.

Exact Form:

15

Decimal Form:

0.2


hope l helped have a good day

3 0
3 years ago
Read 2 more answers
Simplify these expressions. a.2r+3+4r. b.8+3d+d. c.mn+ (-3mm)+6 d. 10s + (-10) + (-4s)
Maru [420]

Step-by-step explanation:

<em>Combine like terms</em>

a. 2r + 3 + 4r = (2r + 4r) + 3 = 6r + 3

b. 8 + 3d + d = (3d + d) + 8 = 4d + 8

c. mn + (-3mn) + 6 = (mn - 3mn) + 6 = -2mn + 6

d. 10s + (-10) + (-4s) = (10s - 4s) - 10 = 14s - 10

<em>Terms are called "like terms" if they have the same variable part (the same letters in the same powers). Like terms differ at most coefficient.</em>

7 0
3 years ago
2log(2a - 1) = 0<br> How
Kryger [21]

Answer:

<h2>a = 1</h2>

Step-by-step explanation:

2\log(2a-1)=0\\\\\text{Domain:}\\\\2a-1>0\qquad\text{add 1 to both sides}\\2a-1+1>0+1\\2a>1\qquad\text{divide both sides by 2}\\\dfrac{2a}{2}>\dfrac{1}{2}\\\boxed{a>0.5}\\============================\\\\2\log(2a-1)=0\qquad\text{divide both sides by 2}\\\\\dfrac{2\!\!\!\!\diagup\log(2a-1)}{2\!\!\!\!\diagup}=\dfrac{0}{2}\\\\\log(2a-1)=0\qquad\text{use}\ \log_ab=c\iff b=a^c\\\\\log(2a-1)=\log10^0\\\\\log(2a-1)=\log1\iff2a-1=1\qquad\text{add 1 to both sides}\\\\2a-1+1=1+1\\\\2a=2\qquad\text{divide both sides by 2}\\\\\dfrac{2a}{2}=\dfrac{2}{2}\\\\a=1\in D

3 0
3 years ago
Pls help<br> Find the measurements of those
ch4aika [34]

Answer:

i think C

im not really sure

8 0
2 years ago
2log 10 =0.3010,then find the value of 22log 8
skad [1K]

Answer:

2.99

Step-by-step explanation:

                                                       <em>Note: [log10 = 1]</em>

<em>                                                        [log8  = 0.903089987]</em>    

2log10 = 0.3010

<em>   </em>22log8 = x

Therefore:

<em>2log10 x = 22log8</em>

<em>x = 2.99</em>

<em>  </em>

5 0
3 years ago
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