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uranmaximum [27]
3 years ago
11

Jake is building a circular sandbox for his son. How many plastic blocks will he need to make one layer around the sandbox?

Mathematics
2 answers:
irakobra [83]3 years ago
8 0

Answer:

35

Step-by-step explanation:

densk [106]3 years ago
4 0

Answer:

6.28(r)  

r = #blocks

Step-by-step explanation:

circumference = 2pi(r)

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use the substitution method to solve the system of equations choose the correct orderd pair. 3x-y=7 2x-2y=2
sergey [27]

Answer:

(3,2)

Step-by-step explanation:

We are given the system:

3x-y=7

2x-2y=2.

We are asked to solve this by substitution.  We need to pick an equation and pick a variable from that equation to solve for that variable.

I really like either for this.  Some people might go with the first one though. Let's do that.  I will solve the first one for y.

3x-y=7

Subtract 3x on both sides:

   -y=-3x+7

Divide both sides by -1:

     y=3x-7

Now we are ready for substitution.  We are going to plug this equation into the second equation giving us:

2x-2y=2 with y=3x-7 gives us:

2x-2(3x-7)=2

Distribute:

2x-6x+14=2

Combine like terms:

-4x+14=2

Subtract 14 on both sides:

-4x      =2-14

Simplify:

-4x       =-12

Divide both sides by -4:

  x       =-12/-4

Simplify:

 x         =3

So using y=3x-7 and x=3, I will find y now.

y=3x-7 if x=3

y=3(3)-7   (I inserted 3 for x since we had x=3)

y=9-7       (Simplified)

y=2           (Simplified)

The answer is (x,y)=(3,2).

6 0
3 years ago
The given line passes through the points (0, -3) and (2, 3).
puteri [66]

The equation, in point-slope form of the line that is  parallel to the given line and passes through the point  (-1, -1) is y + 1 = 3(x + 1).

<u>Solution:</u>

Given that, a line passes through (0, -3) and (2, 3).

We have to find the line equation which is parallel to above line and  passes through (-1, -1).

Now, let us find the slope of the given line.

\text { slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}, \text { where }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are points on that line }

\text { Then, } m=\frac{3-(-3)}{2-0}=\frac{3+3}{2}=\frac{6}{2}=3

So, slope of given line is 3,  

Then, slope of required line is also 3, as slopes of parallel lines are equal.

Then, required line equation in point – slope form is given as:

\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right)} \\\\ {y-(-1)=3(x-(-1))} \\\\ {\rightarrow y+1=3(x+1)}\end{array}

Hence, the line equation is y + 1 = 3(x + 1).

6 0
3 years ago
Mr. Spence asks his math students to identify TWO shapes based on the
ale4655 [162]

Answer:

Step-by-step explanation:

d

6 0
3 years ago
A right triangle is formed by connecting coordinates (5, -2), (2, -3), and (-1, 6). What is the area of the triangle in square u
Marianna [84]

Answer:

the triangle formed from the coords is 3cm by 9cm so try 3 × 9 = 27 then 27 ÷ 2 = 13.5 from the formula a = ½bh?

Step-by-step explanation:

8 0
2 years ago
How do I solve for a right triangle
Scrat [10]

Answer:

The angle of depression is the angle below straight ahead -- horizontal -- that an observer must look in order to see something below the observer.

6 0
3 years ago
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