Recall that to get the x-intercepts, we set the f(x) = y = 0, thus
![\bf \stackrel{f(x)}{0}=-4cos\left(x-\frac{\pi }{2} \right)\implies 0=cos\left(x-\frac{\pi }{2} \right) \\\\\\ cos^{-1}(0)=cos^{-1}\left[ cos\left(x-\frac{\pi }{2} \right) \right]\implies cos^{-1}(0)=x-\cfrac{\pi }{2} \\\\\\ x-\cfrac{\pi }{2}= \begin{cases} \frac{\pi }{2}\\\\ \frac{3\pi }{2} \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bf%28x%29%7D%7B0%7D%3D-4cos%5Cleft%28x-%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%20%5Cright%29%5Cimplies%200%3Dcos%5Cleft%28x-%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%20%5Cright%29%0A%5C%5C%5C%5C%5C%5C%0Acos%5E%7B-1%7D%280%29%3Dcos%5E%7B-1%7D%5Cleft%5B%20cos%5Cleft%28x-%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%20%5Cright%29%20%5Cright%5D%5Cimplies%20cos%5E%7B-1%7D%280%29%3Dx-%5Ccfrac%7B%5Cpi%20%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0Ax-%5Ccfrac%7B%5Cpi%20%7D%7B2%7D%3D%0A%5Cbegin%7Bcases%7D%0A%5Cfrac%7B%5Cpi%20%7D%7B2%7D%5C%5C%5C%5C%0A%5Cfrac%7B3%5Cpi%20%7D%7B2%7D%0A%5Cend%7Bcases%7D)
Given: BD bisects AC and ∠CBE≅∠ADE. Prove: ABCD is a parallelogram.
2 answers:
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Answer:
(9, <u>81</u>) (<u>8</u>, 71)
Step-by-step explanation:
My explanation is in the picture. All I did was replace the known variable with the proper letter!
Answer:
B
Step-by-step explanation:
<u>To find the answer, you have to </u><u>multiply each term of the first parenthesis' expression with each term in the next parenthesis' expression.</u><u> Then </u><u>combine like terms</u><u>.</u> So we have:
Answer choice B is right.
A.) the degrees inside the triangles are 50, 70, and 60. you know because 180-120=60
b.) you know that they are similar triangles because they have the same angle degrees.
im not sure if this is correct but i think it is :)
b.) you know that they are similar triangles because they have the same angle degrees.
im not sure if this is correct but i think it is :)