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Arte-miy333 [17]
2 years ago
9

What is the solution to the following system of equations?

Mathematics
1 answer:
babunello [35]2 years ago
3 0

Answer:

simple quadratics

Step-by-step explanation:

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A researcher measures the mean time (in seconds) it takes two groups of children to complete an activity test. She finds that gr
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4 0
3 years ago
Rewrite the equation without absolute value, thanks!
34kurt

Since x - 3 < 0 for -2 < x < 3, |x-3| = -(x-3)

Since x + 2 > 0 for -2 < x < 3, |x+2| = x+2

Since x - 5 < 0 for -2 < x < 3, |x-5| = -(x-5).

So y = -(x-3) + (x+2) -(-(x-5)) = 3 - x + x + 2 + x - 5 = x.

y = x, if -2 < x < 3.

4 0
3 years ago
The sum of two natural numbers is 474. One has the digit 1 as its rightmost digit. If this digit is removed from the number, the
Olenka [21]

Answer:

431 and 43

Step-by-step explanation:

Two numbers: y1 and y

Number one: y1 = 10 * y + 1

(10 * y + 1) + y = 474

11y = 473

y = 43

Two numbers: 431 and 43

check: 431 remove 1 (digit) -> 43

431+43=474

8 0
3 years ago
In which quadrant is sec e&lt; 0 and tan e &gt; 0?
iren2701 [21]

Answer:

C

Step-by-step explanation:

Because Tangent is positive in third quadrant

7 0
3 years ago
#5 The MAC is 4 centimeters. Find the circumference of B. Round your answer to the hundredths.
bixtya [17]

Answer:

C ≈ 11.71 cm

Step-by-step explanation:

using the ratio arc  AC : circumference C = angle at centre of sector : 360°

\frac{AC}{C} = \frac{123}{360} , that is

\frac{4}{C} = \frac{123}{360} ( cross- multiply )

123 × C = 4 × 360 = 1440 ( divide both sides by 123 )

C = \frac{1440}{123} ≈ 11.71 cm ( to the nearest hundredth )

6 0
3 years ago
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