The principle is called CEPHALOCAUDAL PRINCIPLE.
This principle proposed that growth follow a particular pattern in which the head and the upper part of the body grow first before the growth proceeds to other part of the body.
Answer:
50% or 1/2. The result remains unchanged if the husband were to have G6PD.
Explanation:
For X-linked recessive inheritance, a female (XX) needs two recessive alleles to be affected while a male needs only one (XY). It is hypothetically assumed that the Y chromosome does not carry any trait.
Assuming the allele for the disease is represented by g, a woman whose father suffered from G6PD is a carrier for the disease with genotype 
. A normal man will have the genotype 
. When the 2 marries:
x = 
It thus means that 50% or 1/2 of their sons will be expected to have G6PD.
Now, assuming the husband has G6PD, the mating becomes:
x 
= 
50% or 1/2 of their sons is still expected to have G6PD. The ratio remains unchanged.
Answer:
The correct answer is 50%.
Explanation:
In the given question, the table says that fruit color is determined by the incomplete dominance of allele R and R'. In the case of RR genotype the fruit color will be red and R'R' the food color will be yellow but in the heterozygous condition the color would be orange, so the cross between RR' and R'R' would be as follow:
Punnett square:
R R'
R' RR' R'R'
R' RR' R'R'
It is found by the given cross that the cross between RR' and R'R' would form two orange fruit plants out of four which is 50%
Answer:
The correct answer is -
P1: SSyy
p2: ssYY
Explanation:
In the given question it is given that S is the allele for the dominant trait of spherical shape over s allele of dented shape and similarly Yellow pea seed is dominant over y green seed.
It is given that parent 1 or p1 is true breeding for green spherical shaped seeds which means it has two alleles of the same gene that are SSyy (S for spherical and y for green) and parent 2 or p2 is a pure bred plant with yellow dented shaped seeds that would be ssYY.
