Explanation:
There is a high degree of informality to these relationships, which are focused on information sharing, joint-problem solving and joint operations.
A hallmark of most of these processes is their informality, whether through information sharing, joint problem solving or joint operations.
Global joint problem-solving team. In addition to requesting a division of labour, the Global Task Team recommendations called upon the World Health Organization (WHO), UNICEF, the United Nations Population Fund (UNFPA), the United Nations Development Programme (UNDP), the World Bank, the UNAIDS Secretariat and the Global Fund to take the lead in and establish the joint United Nations system-Global Fund problem-solving team by July # in order to support efforts that address implementation bottlenecks at the country level
Answer:
1. Mass Storage Devices
2. Available Storage Space
3. Data Access Performance
4. Device Form Factor and Connection
<span>Jun 15, 2011 - Multiplication and division can be achieved using bit operators, for example .... I discovered pretty much the same thing for Sun CC close to 20 years ago. ... Just to add a rough estimation: On a typical 16-Bit processor ..... Doing it yourself willaffect readability and possibly have no effect on performance.</span><span>
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Answer:
Explanation:
Following are the Semaphores:
Customers: Counts waiting customers;
Barbers: Number of idle barbers (0 or 1)
mutex: Used for mutual exclusion.
Cutting: Ensures that the barber won’t cut another customer’s hair before the previous customer leaves
Shared data variable:
count_cust: Counts waiting customers. ------------copy of customers. As value of semaphores can’t access directly.
// shared data
semaphore customers = 0; semaphore barbers = 0; semaphore cutting = 0; semaphore mutex = 1;
int count_cust= 0;
void barber() {
while(true) { //shop is always open
wait(customers); //sleep when there are no waiting customers
wait(mutex); //mutex for accessing customers1
count_cust= count_cust-1; //customer left
signal(barbers);
signal(mutex);
cut_hair();
}
}
void customer() {
wait(mutex); //mutex for accessing count_cust
if (count_cust< n) {
count_cust= count_cust+1; //new customer
signal(customers); signal(mutex);
wait(barbers); //wait for available barbers get_haircut();
}
else { //do nothing (leave) when all chairs are used. signal(mutex);
}
}
cut_hair(){ waiting(cutting);
}
get_haircut(){
get hair cut for some time; signal(cutting);
}
