Answer:
The Last option: Dyadic Communication AND Interpersonal Communication
is the correct one.
Explanation:
Communication can be defined as the process in which one may convey his thoughts or inquires about things.
There are many types of communications as listed above.
- Intrapersonal Communication
- Interpersonal Communication
- Dyadic Communication
- Small Group Communication
- Public Communication
- Mass Communication
- Organizational Communication
- Intercultural Communication.
Under all these, Interpersonal communication and Dyadic communication are the ones that are between two people.
Dyadic communication is the one in which two people relate to exchange thoughts and ideas face-to-face. It is sometimes referred as dialogic relation.
Interpersonal relation can be between two or more than two persons that may know each other. It is clearly specified in this communication that who listener and speaker are.
<h3>I hope it will help you!</h3>
1.
#include <iostream>#include <string>
using namespace std;
int main(){ string chars; // This is where we will put our @ signs and print them for(int x=0;x < 5; x++){
chars = chars + '@'; // This will concatenate an @ sign at the end of the variable cout << chars << "\n"; }}
2.
#include <iostream>#include <string>
using namespace std;
int main(){ string name; // Our variable to store the name cout << "What is your name? \n"; // Asks the user for their name cin >> name; cout << "\nWell, hello " << name << "!";}
3.
#include <iostream>#include <string>
using namespace std;
int main(){ int number; // Our variable cout << "Enter a number\n"; // Asks for a number cin >> number; cout << "You entered " << number << "%!";}
4.
#include <iostream>#include <string>
using namespace std;
int main(){ int number; // Our variable cout << "Enter a number\n"; cin >> number;
int check = number % 2; // The modulo operator (the percent sign) gets the remainder of the quotient if (check == 0) { cout << number << " is even!"; // If the remainder is 0 then it prints out "x is even" } else { cout << number << " is odd!"; // If the remainder is not 0 then it prints out "x is odd" }}
5.
#include <iostream>#include <string>
using namespace std;
int main(){ float r; // Our variable cout << "Enter a radius\n"; cin >> r; if (r < 0){ cout << "Lol. No."; // If the radius is less than zero print out that message } float circumference=2*3.14*r; float area=r*r*3.14; cout << "\n\n Circumference of circle: " << circumference; cout << "\n Area of circle: " << area;}
Answer:
Yes.
Explanation:
Race condition can be described as a situation where at any time there are two or more processes or threads operating concurrently, there is potential for a particularly difficult class of problems. The identifying characteristic of race conditions is that the performance varies depending on which process or thread executes their instructions before the other one, and this becomes a problem when the program runs correctly in some instances and incorrectly in others. Race conditions are notoriously difficult to debug, because they are unpredictable, unrepeatable, and may not exhibit themselves for years.
Microsoft.././/.//././././././.
