Question

Three beads are picked from a bag containing 5 white beads and 4 yellow beads. Note that each bead is put back before the next is selected. Find the probability of picking one yellow and two white beads.

Answer 1

Answer:

100/729

Step-by-step explanation:

The probability of picking a yellow bead is 4/9, since there are 4 yellow beads in the bag and 9 beads in total. The probability of picking white beads both times is 5/9, for the same reason. Therefore, the probability of these events happening is 4/9*5/9*5/9=100/729. Hope this helps!

Answer 2

Answer:

$\frac{100}{729}$

Step-by-step explanation:

For this, you need to firstly make the 3 beads a fraction.

Add 5 and 4.

5+4=9

The denominator will be 9 for each fraction.

$\frac{4}{9}$×$\frac{5}{9}$×$\frac{5}{9}$

Now multiply.

$\frac{100}{729}$

You cannot simplify it further so it will stay as the fraction.