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Oliga [24]
3 years ago
14

Nine more than a number divided by six

Mathematics
1 answer:
Vladimir [108]3 years ago
4 0

Answer:

x/6+9

Step-by-step explanation:

you are adding 9 to a number divided by six. you don't know the number so you put x. x divided by 6 can be put as a fraction with x/6 or x over 6. you then have x/6, and you need to add 9. it ends up being x/6 + 9

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Marysya12 [62]

Answer:

If d is the height of the tree: d = 1/2m

Step-by-step explanation:

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.36 (6 repeating) as a fraction in simplest form?
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What are the period and phase shift for f(x) = 3 tan(4x + π)?
Y_Kistochka [10]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal or "phase" shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}


now.. with that template above in mind, let's see yours


\bf \begin{array}{lllllll}
f(x)=&3tan(&4x+&\pi )\\
f(x)=&3tan(&4x+&1\pi )&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}

7 0
3 years ago
Raju’s mother is four times as old as Raju. After 5 years , her mother will be three
cluponka [151]

Answer:

Mother: 40 years old

Rakhi: 15 years old

Step-by-step explanation:

Solution :

Let present age of Rakhi = x years

Present age of Mother = 4x

5 years later

Age of Rakhi =x+5

Ag of Mother =4x+5

Given 4x+5=3(x+5)

4x−3x=15−5

⇒x=10

Mother's age =4x=40 years

Plug 10 in for x to find Rakhis age

7 0
3 years ago
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