1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
8_murik_8 [283]
3 years ago
9

Find A10 where A- ܢ ( 1-2 8 0 -1 0 0_0 -1

Mathematics
1 answer:
trasher [3.6K]3 years ago
6 0

Answer:

worng question

1.....................

You might be interested in
Is this graph a linear or no linear function?
olga2289 [7]

it is nonlinear function

5 0
3 years ago
Read 2 more answers
Really need help with this PLZZZZZ WILL GIVE BRAINLIEST PLZZ ASAP I SUCK AT MATHHH
shusha [124]

I'm not sure about the second image.

But the first one is telling you to translate x, 3 units left, and translate y, 4 units up.

(-6, 0) will turn to (-9, 4)

I subtracted 3 from -6 and added 4 to 0.

7 0
3 years ago
Find the 2th term of the expansion of (a-b)^4.​
vladimir1956 [14]

The second term of the expansion is -4a^3b.

Solution:

Given expression:

(a-b)^4

To find the second term of the expansion.

(a-b)^4

Using Binomial theorem,

(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}

Here, a = a and b = –b

$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}

Substitute i = 0, we get

$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4

Substitute i = 1, we get

$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b

Substitute i = 2, we get

$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}

Substitute i = 3, we get

$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}

Substitute i = 4, we get

$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}

Therefore,

$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}

=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}

Hence the second term of the expansion is -4a^3b.

3 0
3 years ago
Can you guys help me asap
stepladder [879]
The answer should be D.
7 0
3 years ago
41°F equals how many degrees Celsius? A. –5°C B. 5°C C. 9°C D. 56°C
Ludmilka [50]
The answer is B. 5 degrees celcius
The formula is
(temprature in celcius)=(temprature in fahrenheit -32) *5/9
or
Temprature in celcius=( temprature in fahrenheit-32) * 1.8
5 0
3 years ago
Other questions:
  • The quotient of the sum of 2t and 2 and twice the cube of s
    9·1 answer
  • Determine the value of B such that the line defined by 8x + By + 92 = 0 passes through the point (-4,12).
    6·1 answer
  • Which expression has a value that is more than its base?
    15·1 answer
  • What is the order pair for the orgin
    6·1 answer
  • Part A
    11·1 answer
  • Walter slater sells appliances and earns 2.5 percent commission in addition to his salary. last month he sold $63,000 in applian
    11·2 answers
  • Response will be saved automatically.
    7·1 answer
  • Four more than five times a number is -16. What's the number
    11·1 answer
  • HELP PLZ I WILL GIVE BRAINLIEST!!! Write the prime factorization of 675 using exponents.
    9·1 answer
  • Write a linear function that models each situation. a 24. The enrollment at a local community college was 5,000 in 1960. In the
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!