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3 years ago

11

Jane borrows $4000 dollars from her bank.she has a simple interest loan at 5% interest rate and will pay it back over 4 years ho

w much interest will she pay back

1 answer:

Tom [10]3 years ago

4 0

4000x.05=200*4= 800

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Two rectangles, A and B are in proportion in ihe ratio 3 : 5. If the area of Rectangle B is 80 cm?, find the area of Rectangle A

butalik [34]

Answer:

the area of rectangle A is 133.33 sq cm

Step-by-step explanation:

let us suppose area of rectangle A be x....hence we get ,

3:5=80/x

or,3/5=80/x

or,3x=80*5

or,x=400/3

x=133.3.3

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2 years ago

The figure is made up of a semicircle and a triangle. Find the perimeter. Round your answer to the nearest hundredth.

grandymaker [24]

I think your answer is 56

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3 years ago

Can somebody helppp ??

mario62 [17]

Answer:

10

Step-by-step explanation:

Since F is the midpoint of EG, EF and FG are equal. We know that FG is 4 units, so EF must be 4 units. We also know that FH and EF make EH, so we substitute the values that we have.

FH + EF = EH

6 + 4 = EH

EH = 10

3 0

3 years ago

Read 2 more answers

#8 please. GCF of 117, 99, and 126

Advocard [28]

The factors of 117 are: 1, 3, 9, 13, 39, and 117
The factors of 99 are: 1, 3, 9, 11, 33, and 99
The factors of 126 are: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, and 126

The greatest common factors of 117, 99, and 126 are: 1, 3, and 9. And according to your answer choices your answer is C. 9

7 0

3 years ago

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago