The area of the circle is 18
ANSWER:
Let t = logtan[x/2]
⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx
⇒dt = 1/2 cos² x/2 × cot x/2dx
⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx
⇒dt = 1/2 cosx/2 / sin x/2 dx
⇒dt = 1/sinxdx
⇒dt = cosecxdx
Putting it in the integration we get,
∫cosecx / log tan(x/2)dx
= ∫dt/t
= log∣t∣+c
= log∣logtan x/2∣+c where t = logtan x/2
68-33 blockers ?????????????????????????????????????????!?!!
The interest rate on her account would be 38.4%.
If we use the simple interest formula I=PrT, the principle (P) would be 6000. Assuming that it is based on annual interest, the time (t) would be 1/12. Then, you multiply 6000 by 1/12 to get 500. Finally you divide 192/500 and then multiply by 100.
If the time is based on monthly payments, then do the same thing, except multiply 6000 by 1
