H>12 and w>12 however p≤60
p=2(h+w) but give what we have above for h and w
p>48 so p must satisfy the solution set:
48<p≤60 and since p=2(h+w)
48<2(h+w)≤60
24<h+w≤30
So there are infinitely many solutions if h and w are not restricted to integer values...
(h,w) vary from (12,18) to (18,12) Note that neither endpoints exist, 12 because it is explicitly excluded and 18 because that would make the other dimension 12 which is excluded...
Now if you are just talking integer values, there are only:
(13,17),(14,16),(15,15),(16,14),(17,13)
To keep the fire burning for 18 hours, she needs 18/4 times 6=27 logs.
Answer: (-6,-5)
Step-by-step explanation:
2x - 2y = -2 ............ equation 1
3x - y = -13 ................ equation 2
solving by substitution method
from equation 2 , make y the subject of the formula, we have
y = 3x + 13 .............. equation 3
substitute equation 3 into equation 1 , we have
2x - 2 (3x + 13 ) = -2
2x - 6x - 26 = -2
-4x - 26 = -2
-4x = -2 +26
-4x = 24
x = 24/-4
x = -6
substitute x = -6 into equation 3 to get the value of y , we have
y = 3(-6) + 13
y = -18 +13
y = -5
First move the -8 on the left to the right. this makes the inequality become 8x≤-64. Then you want to isolate the x by dividing 8x by 8, and make sure to do the same to -64. This makes it become x<span>≤-8, which is your final answer! Hope this helped :)</span>
I am pretty sure the answer is A.One