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3 years ago

14

A castle has to be guarded 24 hours a day five knights are ordered to split each day's guard duty equally how long will each kni

ght spend on guard duty in one day? Record your answer in hours.

1 answer:

disa [49]3 years ago

4 0

Answer:

Each knight will 4.8 hrs spend on guard in one day

Step-by-step explanation:

A castle has to be guarded 24 hours a day 5 knights are ordered to split each day's guard duty equally

Each knights has to guard equally l.e for equal time .

That means 24 hours time has to be equally divided among the 5 knights

= 24 / 5 = 4.8

Each knight will spend on guard in one day = 4.8 hrs

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A water wheel has a radius measuring between 13 feet and 24 feet. The wheel is able to turn 7π9 radians from its starting positi

madam [21]

Answer:

31.76 ft and 58.64 ft

Step-by-step explanation:

The radius measures between 13 feet and 24 feet.

The wheel is able to turn 7π/9 radians before getting stuck.

We need to find the range of distances that the wheel could spin before getting stuck. That is, the length of arc.

Length of an arc is given as:

$L = \frac{\theta}{2\pi} * 2\pi r$

where θ = central angle = 7π/9 radians

r = radius of the circle

Therefore, for 13 feet:

$L = \frac{7\pi}{18 \pi} * 2 * \pi * 13\\\\L = 31.76 ft$

For 24 feet:

$L = \frac{7\pi}{18 \pi} * 2 * \pi * 24\\\\L = 58.64 ft$

The wheel could spin between 31.76 ft and 58.64 ft before getting stuck.

4 0

3 years ago

Now there is a square city of unknown size with a gate at the center of each side. There is a tree 20 b from the north gate. Tha

Brums [2.3K]

Answer:

The length of each side of the city is 250b

Step-by-step explanation:

Given

$a = 20$ --- tree distance from north gate

$b =14$ --- movement from south gate

$c = 1775$ --- movement in west direction from (b)

See attachment for illustration

Required

Find x

To do this, we have:

$\triangle ADE \sim \triangle ACB$ --- similar triangles

So, we have the following equivalent ratios

$AE:DE = AB:CB$

Where:

$AE = 20\\ DE = x/2 \\ AB = 20 + x + 14 \\ CB = 1775$

Substitute these in the above equation

$20:x/2 = 20 + x + 14: 1775$

$20:x/2 = x + 34: 1775$

Express as fraction

$\frac{20}{x/2} = \frac{x + 34}{1775}$

$\frac{40}{x} = \frac{x + 34}{1775}$

Cross multiply

$x *(x + 34) = 1775 * 40$

Open bracket

$x^2 + 34x = 71000$

Rewrite as:

$x^2 + 34x - 71000 = 0$

Expand

$x^2 + 284x -250x - 71000 = 0$

Factorize

$x(x + 284) -250(x + 284)= 0$

Factor out x + 284

$(x - 250)(x + 284)= 0$

Split

$x - 250 = 0 \ or\ x + 284= 0$

Solve for x

$x = 250 \ or\ x =- 284$

x can't be negative;

So:

$x = 250$

6 0

3 years ago

Write an expression for this one <br> the sum of an odd integer and the next odd integer.

Sidana [21]

Let x is the odd integer
x +2 is the next odd integer
so sum of an odd integer and the next odd integer:
x + (x+2)

8 0

3 years ago

A landscaper charges you $102 to plant 8 bushes in front of your office building. If you decide to put 12 much of the same bushe

Korolek [52]

$102/8=$12.75 per bush
12 × $12.75=$153

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3 years ago

Read 2 more answers

Does anyone know the answer to these problems if you know the answer for the first question then put 5. and your answer same goe

Anettt [7]

Number 5) A hill that rises 2 feet for every 10 feet of run. Because a longer run is not as steep as a short run.

Number 6) They all are parallel, they do not intersect.

6 0

3 years ago