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3 years ago

I just need help it’s algebra 2

Mathematics

2 answers:

frez [133]3 years ago

8 0

Answer:

1) will be two infinitely negative numbers with a higher max at about -1.5 and a lower max at (1, -2).

2) will be in an N shape, with a peak at (0,1). The left side of the n will be negative x and vice versa for the right side.

3) will be in a W shape, left and rights are the same as 2), peak at (.5, 1.25).

4) will be in a reverse N shape, peaking at (0, 36)

Step-by-step explanation:

Check a graphing calculator and use trace function.

Hope it helps!

Simora [160]3 years ago

4 0

Answer: It's the first one because a polynomial function is always going to be F(x). Remember that!

Step-by-step explanation:

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ANSWER
${a}^{3} + {b}^{3} = (a + b)( {a}^{2 } - ab + {b}^{2} )$

EXPLANATION

To find the expression that is equivalent to
${a}^{3} + {b}^{3}$
we must first expand
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Then we rearrange to find the required expression.

So let's get started.

${(a + b)}^{3} = (a + b) {(a + b)}^{2}$

We expand the parenthesis on the right hand side to get,

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We expand again to obtain,

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Let us group the cubed terms on the right hand side to get,

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2}b + 3a {b}^{2}$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab (a+ b)$

We make the cubed terms the subject,

${(a + b)}^{3} - 3ab (a+ b) = {a}^{3} + {b}^{3}$

We factor to get,

$(a + b)({(a + b)}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We expand the bracket on the left hand side to get,

$(a + b)( {a}^{2} + 2ab + {b}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We finally simplify to get,

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