Use the Functions given to evaluate f(g(-1)) =

Mathematics

1 answer:

Juliette [100K]2 years ago

5 0

The answer would be -fg But, I'm not so sure about the graph so sorry!

You might be interested in

Joshua uses a rule to write the following sequence of numbers 1/6,1/2,5/6,----------,11/2 What rule did Joshua use? What is the

Pani-rosa [81]

Answer: The missing number in the sequence is $\frac{7}{6}$

Step-by-step explanation:

Since we have given that

$\frac{1}{6},\frac{1}{2},\frac{5}{6},----------,\frac{11}{2}$

First term = a= $\frac{1}{6}$

Common difference = d is given by

$d=a_2-a_1\\\\\frac{1}{2}-\frac{1}{6}\\\\=\frac{6-2}{12}\\\\=\frac{4}{12}=\frac{1}{3}\\\\Similarly,\\d=a_3-a_2\\\\=\frac{5}{6}-\frac{1}{2}\\\\=\frac{10-6}{12}\\\\=\frac{4}{12}\\\\=\frac{1}{3}$

Therefore, it forms an arithmetic sequence.

Since, $a_4$ is missing,

So,

$a_4=a+3d\\\\a_4=\frac{1}{6}+3\times \frac{1}{3}\\\\a_4=\frac{1}{6}+1\\\\a_4=\frac{1+6}{6}\\\\a_4=\frac{7}{6}$

Hence, the missing number in the sequence is $\frac{7}{6}$

4 0

2 years ago

Read 2 more answers

What number should be added to both sides of the equation to complete the square? x2 + 3x = 6

sladkih [1.3K]

The answer is B because you are suppose to square and divide once you subtract 6 on both sides.

3 0

2 years ago

Read 2 more answers

This year, 1,272 students enrolled in night courses a a local college. Last year only 1,200 students enrolled. What was the perc

Ahat [919]

The percent increase in enrollment is 6 %

The operation used in first step is finding the difference between final value and initial value

<h3><u>Solution:</u></h3>

Given that This year, 1,272 students enrolled in night courses a a local college

Last year only 1,200 students enrolled.

To find: percent increase in the enrollment

The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.

<em><u>The percent increase is given as:</u></em>

$\text { percentage increase }=\frac{\text { final value - initial value}}{\text { initial value }} \times 100$

Here initial value (last year) = 1200 and final value(this year) = 1272

Substituting the values in above formula,

$\begin{aligned}&\text { percentage increase }=\frac{1272-1200}{1200} \times 100\\\\&\text { percentage increase }=\frac{72}{1200} \times 100=6\end{aligned}$