Answer:15-45 and 20 hope this helps
Step-by-step explanation:
The number of students would not change between before the test and after the test. 3+8 and 4+7 both = 11 so finding out how many students would equal one ratio can then be used to find how many equal 3 and 8.
If 92 students are equal to 4 in the ratio, then 1 in the ratio is worth 23 students. This is important as then when you times 23 by 7 you find out how many students there are in the regular maths class, 161 students. Plussing these two together gives you a total of 253 students.
Using this 253 you can divide it by 11 to find out how much 1 number would be in the ratio, it equals 23. Using this you can then times 23 by both 3 and 8 to find the original class sizes, 3x23 = 69, and 23x8 = 184.
Making the origional class size of the advaced class 69 studnets, and the regular maths class size 184.
Answer:
1312.5 cubic feet
Step-by-step explanation:
Let the swimming pool be a rectangular prism
The volume of a rectangular prism is:
Volume = length * width * depth
Length = 25 (given)
Width = 15 (given)
The depth is 4ft, but they want the volume when water is 6 inches FROM THE TOP, that is, out of 4 feet, 6 inches (1/2 feet) IS NOT FILLED. So the depth of water is
4 - 1/2 = 3.5 feet
So, we can say
Depth = 3.5 (found)
Hence, the volume would be:
Volume = 25 * 15 * 3.5 = 1312.5 cubic feet
Answer:
PEMDAS
Step-by-step explanation:
you can solve this, just remember pemdas
<span>I believe it is that a two-dimensional sketch doesn't include depth however the isometric sketch does</span>
