Answer:
b
Step-by-step explanation:
you can use trial and error to solve this btw that's what I used and once I got to answer choice b, i plugged in the 2 numbers into the equation based of of their axis once i did that the equation now looked like this 9=3+3, when you solve this the equation would then look like this 9=6 and we both know that 9 doesn't not equal 6 so that is your answer.
Adding a negative is same as subtraction
-5+78-32
73-32
41
You can't solve it, but you can simplify it
-2/3 * (12c - 9) + 14c = -2/3*12c - (-2/3)*9 + 14c = -8c + 6 + 14 c = 6c + 6
Answer:
where a>0.
To graph the the polynomial, begin in the left top of quadrant 2. Then draw downwards to the first real zero on the x-axis at -2. Cross the x-axis and then curve back up to 1/2 on the x-axis. Cross through again and curve back down to cross for the last time at 3 on the x-axis. The graph then ends going down towards the right in quadrant 4. It forms an s shape.
Step-by-step explanation:
The real zeros are the result of setting each factor of the polynomial to zero. By reversing this process, we find:
- zero 1/2 is factor (2x-1)
We write them together with an unknown leading coefficient a which is negative so -a.
where a>0
The leading coefficient of a polynomial determines the direction of the graph's end behavior.
- A positive leading coefficient has the end behavior point up when an even degree and point opposite directions when an odd degree with the left down and the right up.
- A negative leading coefficient has the end behavior point down when an even degree and point opposite directions when an odd degree with the left up and the right down.
- This graph has all odd multiplicity. The graph will cross through the x-axis each time at its real zeros.
To graph the the polynomial, begin in the left top of quadrant 2. Then draw downwards to the first real zero on the x-axis at -2. Cross the x-axis and then curve back up to 1/2 on the x-axis. Cross through again and curve back down to cross for the last time at 3 on the x-axis. The graph then ends going down towards the right in quadrant 4. It forms an s shape.
The answer would be approximately 56.52 inches squared.
You are suppose to find the lateral surface area, since the label only go around the can, excluding the top and bottom.
To find the lateral surface area, you'd need to find the circumference of the circle, and then multiply that by the height.
Since C = πd, 3.14..*3 ≈ 9.42. And 9.42*6 = 56.52. Conclusively, the approximate amount of paper needed to make the can's label would be about 56.52 inches squared.