Answer: x = 17/3 or 5 2/3
Step-by-step explanation:
Let the number be x
ATQ
6(x -4) = 10
6x-24 = 10
6x = 10+24
6x = 34
x = 34/6
x = 17/3
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11 a. Since she runs 10km in one hour she runs 5km in half an hour and 25km in 2 and a half hours
11b. Since she runs 5 miles in one hour she runs 2.5 miles in half an hour and 12.5 mils in 2 and a half hours
11 c. Since 1.60934 kilometers = 1 mile, Clair ran the farther distance
12 a. 13.20/6 = 2.2 dollars for 1 bowl
12 b. 9/3 = 3 and if he got 3 sets of 3 free bowls he bought 24 pairs of glasses
12 c. If Malcom bought 24 pairs of glasses 24*1.80 = 43.2, so he spent 43.2 dollars on glasses
13 a. 6 to 4 or 6:4
Y = -1 is a horizontal line going through "-1" on the y axis
Note that the point (1,2) is exactly 3 units of distance above the line y = -1
When we reflect across this line, the point (1,2) will just move straight down to exactly 3 units of space below the line y = -1. Since we are not shifting left or right, the x coordinate of our original point will not change. The y coordinate of our original point will now need to be reduced by 6(3 units down to get to the line of reflection and then 3 more down to get to the image location)
The coordinates of the image point will be (1, -4)
Now we need to do the same process with (1, -4) being reflected across y=1
Note (1,-4) is 5 units of distance below the line y = 1 , so we need to reflect the point upward so that the image point is located exactly 5 units of distance above the line y = 1 Again, the x coordinate does not change, and our final image coordinates are (1, 6)
I guess more simply stated, if you're just looking for the number in the green box it would be " 1 " .. Reflecting points across horizontal lines only result in changes of the "y" coordinate since there is no shift left or right.
Triangles ABC and LBM are similar. We know this because AL and LB have the same length, so that AB is twice as long as either AL or LB. The same goes for MC and BM, and BC. The angle B is the same for both tirangles ABC and LBM, so the side-angle-side postulate tells us the triangles are similar, and in particular that triangle ABC is twice as large as LBM.
All this to say that LM must be half as long as AC, so LM has length (B) 14 cm.