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Lubov Fominskaja [6]
3 years ago
10

Find the value of the variable if P is between J & K. A) JP = 8z - 17 B) PK = 5z + 37 C) JK = 17z - 4

Mathematics
2 answers:
Daniel [21]3 years ago
3 0
<span>We cannot deduce about the exact location of P between J and K. But we can conclude: segment JP + segment PK = line JK.
</span><span>JP + PK = JK.
</span><span>Substitute first each.
(8z - 17) + (5z + 37) = 17z - 4
Combine like terms.
13z + 20 = 17z - 4
Isolate the variable z.
4z = 24
z = 6
The value of the variable z is then 6 units.</span>
Reptile [31]3 years ago
3 0
<span>From the problem statement, we can say that the sum of segment JP and segment PK is equal to the line JK.

</span><span>JP + PK = JK.

</span><span>First, we substitute the equations to each term.
(8z - 17) + (5z + 37) = 17z - 4 

Combining like terms.
13z + 20 = 17z - 4

Solving for z,
4z = 24 
z = 6

</span>
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A) Dati cinci exemple de numere intregi mai mici ca zero.​
12345 [234]

Answer:

Numerele întregi pozitive sunt toate numerele întregi mai mari decât zero: 1, 2, 3, 4, 5, .... Numere întregi negative sunt toate opusele acestor numere întregi: -1, -2, -3, -4, -5, .... Nu considerăm că zero este un număr pozitiv sau negativ. Pentru fiecare număr întreg pozitiv, există un număr întreg negativ, iar acești numere întregi se numesc opuse. De exemplu, -3 este opusul lui 3, -21 este opusul lui 21 și 8 este opusul lui -8. Dacă un număr întreg este mai mare decât zero, spunem că semnul său este pozitiv. Dacă un număr întreg este mai mic decât zero, spunem că semnul său este negativ.

Step-by-step explanation:

4 0
2 years ago
Match the correct equation for the variable n with * for number of times compound interest is figured. quarterly d.___ semi-annu
Dvinal [7]

Answer:

quarterly N = 4

semi-annually N = 2

Monthly N = 12

annually N = 1

Step-by-step explanation:

Given the following compound interest times :

N = number of times interest is compounded per period :

A period is regarded as a whole year.

Interest compounded;

QUARTERLY = Every 4 months per period = 12/3= 4

SEMI ANNUALLY = Every 6 months per period = 12/6 = 2

MONTHLY = Every month = 12 / 1 = 12

ANNUALLY = Every 12 months = 12 /12 = 1

3 0
2 years ago
Need help how do I do this, start it, and the steps please
Harman [31]
Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

Let's first write down the equation we are going to solve.

( 1 / 3 )h - 4 [ ( 2 / 3 )h - 3 ] = ( 2 / 3 )h - 6

To begin with, we will expand the brackets => [ ]

( 1 / 3 )h - ( 8 / 3 )h + 12 = ( 2 / 3 )h - 6

Next we will collect like terms by placing all the individual numbers on the right-side of the equation and the terms with ( h ) on the left-hand side of the equation so that we can begin making ( h ) the subject.

( 1 / 3 )h - ( 8 / 3 )h - ( 2 / 3 )h = - 6 - 12

Then we will simplify both the left-hand side and right-hand side of the equation to solve it for ( h ).

( - 9 / 3 )h = - 18

- 3h = - 18

h = - 18 / - 3

h = 18 / 3

h = 6

FINAL ANSWER:

Therefore, the answer is:

h = 6

Hope this helps! :)
Have a lovely day! <3
4 0
3 years ago
The sum of three consecutive numbers (numbers in order one after another is 84. What are the three numbers? ________+ ________ +
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Answer:

The answer is 27, 28, 29.

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This is your answer ☺️☺️. If I'm right so,

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