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Novosadov [1.4K]
2 years ago
12

Which ordered pair can be removed so that the resulting graph represents a function?

Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
6 0

Answer:

(1, 3)

Step-by-step explanation:

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Which of the following inequality should be graphed with a dashed line? Select all that apply.
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Answer:

  B, D

Step-by-step explanation:

Any inequality that does not include the "or equal to" case will be graphed with a dashed line.

<h3>Application</h3>

The "or equal to" case is included when the inequality symbol is one of ≤ or ≥. When symbols > or < are used, the boundary line of the solution space is dashed (or the end point on the number line is an open circle).

The inequalities that will be graphed with a dashed line are ...

  • 2x -4y < 12 . . . . choice B
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7 0
2 years ago
Look at the image. (calculus)
mash [69]
<h3>Answer: Choice H)  2</h3>

=============================================

Explanation:

Recall that the pythagorean trig identity is \sin^2 x + \cos^2x = 1

If we were to isolate sine, then,

\sin^2 x + \cos^2x = 1\\\\\sin^2 x = 1-\cos^2x\\\\\sin x = \sqrt{1-\cos^2x}\\\\

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.

Through similar calculations, \cos x = \sqrt{1-\sin^2x}\\\\

Cosine is also positive in this quadrant.

-------------

So,

\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}\\\\\frac{\sin x}{\sin x}+\frac{\cos x}{\cos x}\\\\1+1\\\\2

Therefore,

\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}=2

is an identity as long as 0 < x < pi/2

5 0
2 years ago
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Use the drawing tools to form the correct answers on the grid.
igor_vitrenko [27]

Answer:

The function f(x)= \frac{1}{x^2+2} is continuous for all real numbers

Step-by-step explanation:

To know the possible points of discontinuity of this function, we must find out when the denominator of the function is equal to 0.

The denominator is:

x ^ 2 + 2

Then we equal 0 and clear x

x ^ 2 +2 = 0\\\\x ^ 2 = -2

x ^ 2> 0 for any real number.

This means that

x ^ 2 +2> 0 <em>for all reals numbers</em>.

Therefore, the function f(x)= \frac{1}{x^2+2} is <em>continuous</em> for all real numbers, that is, it does not have discontinuities.

The graphic of this function is shown in the image

4 0
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