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maria [59]
3 years ago
6

Jimmy made 16 quarts of lemon juice. How many liters of lemon juice did Jimmy make? 1 gallon = 4 quarts 1 gallon = 3.785 liters

15.14 19.78 23.78 60.56
Mathematics
2 answers:
olchik [2.2K]3 years ago
8 0

Answer:

15.14 is the answer

Step-by-step explanation:

nexus9112 [7]3 years ago
3 0
The answer is 15.14

1 gallon = 4 quarts
1 gallon = 3.785 liters

16 quarts = 4 gallons
4 x 3.785 = 15.14
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n aquarium holding African cichlids is 6 inches higher than it is wide. Its length is 33 inches, and its volume is 9240 cubic in
sukhopar [10]

Answer: Height = 20 inches

Width = 14 inches

Step-by-step explanation:

The aquarium is rectangular. The formula for determining the volume of a rectangular box is expressed as

Volume = LWH

Where L,W and H represents the length, width and height of the box.

The aquarium holding African cichlids is 6 inches higher than it is wide. It means that

H = W + 6

Its length is 33 inches, and its volume is 9240 cubic inches. It means that

9240 = 33W(W + 6)

9240/33 = W(W + 6)

280 = W² + 6W

W² + 6W + (6/2)² = 280 + (6/2)²

(W + 3)² = 280 + 9 = 289

Taking square root of both sides, it becomes

W + 3 = √289 = 17

W = 17 - 3

W = 14

H = W + 6 = 14 + 6

H = 20

3 0
3 years ago
Suppose you invest $10,410 in equipment to manufacture a new board game. Each game costs $2.65 to manufacture and sells for $20.
leva [86]
Let x= number of board games 
<span>20x=10410+2.65x </span>
<span>-2.65 -2.65 </span>
<span>17.35x=10410 </span>
<span>/17.35 /17.35 </span>
<span>x=600 </span>
<span>You would need to sell at least 600 board games to break even</span>
3 0
3 years ago
Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.
lesya [120]

Answer:

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851

P(sample of 20 boxers is more than 167 pounds)

P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)

= 1 - P(z \leq 0.8438)

Calculation the value from standard normal z table, we have,  

P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

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3 years ago
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Answer: should be x> -18

Step-by-step explanation: hope this helps

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