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Katena32 [7]
3 years ago
14

What is 40 meters in 8 seconds?

Mathematics
2 answers:
Basile [38]3 years ago
4 0

5 meters/ 1 second because if you 40 and 8 you will get 5 and divided 8 by 8 and you get 1, you just divide the denominator by both numerator and denominator.

Scilla [17]3 years ago
3 0

Answer:

5

Step-by-step explanation:

distance over time you divide

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Find the product of 2x^(4x² + 3x + 1). (1 point)
Vladimir79 [104]

Answer:

A - 8x + 6x² + 2x

Step-by-step explanation:

source: trust me bro

6 0
2 years ago
Shani borrowed $5000 at an annual interest rate of 4% compounded yearly. William borrowed the same amount of money at an annual
Natalka [10]

Answer: William will pay $ 330.76 more interest than Shani at the end of 3 years.

Step-by-step explanation:

Compound interest = P((1+r)^t-1)<em> , </em>P= principal , r= rate of interest , t= time

Given: P = $5000 , t= 3 years

For Shani , r= 4% = 0.04

Compound interest = 5000((1+0.04)^3-1)

=5000(1.124864-1)\\\\=5000(0.124864)\\\\=\$\ 624.32

For William, r= 6%= 0.06

Compound interest = 5000((1+0.06)^3-1)

=5000(1.191016-1)\\\\=5000(0.191016)\\\\=\$\ 955.08

Difference = $ ( 955.08- 624.32)

= $ 330.76

Hence, William will pay $ 330.76 more interest than Shani at the end of 3 years.

6 0
3 years ago
9.921 how do you round it to the nearest hundredth 
Evgesh-ka [11]
9.921\to\boxed{9.920}
4 0
2 years ago
Read 2 more answers
URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.
dangina [55]

In the second quadrant, both cos and tan are negative while only sin is positive.

To find tan, we will use the following property below:

\large \boxed{ {tan}^{2}  \theta  =  {sec}^{2}   \theta - 1}

Sec is the reciprocal of cos. If cos is a/b then sec is b/a. Since cos is 2/3 then sec is 3/2

\large{ {tan}^{2}  \theta =  {( -  \frac{3}{2}) }^{2}  - 1} \\   \large{ {tan}^{2}  \theta =   \frac{9}{4}  - 1} \\   \large{ {tan}^{2}  \theta = \frac{9}{4}   -  \frac{4}{4} \longrightarrow  \frac{5}{4}  } \\  \large{tan \theta =  \frac{ \sqrt{5} }{ \sqrt{4} } } \\  \large \boxed{tan \theta =  \frac{ \sqrt{5} }{2} }

Since tan is negative in the second quadrant. Hence,

\large{ \cancel{ tan \theta  =  \frac{ \sqrt{5} }{2} } \longrightarrow \boxed{tan \theta =  -  \frac{ \sqrt{5} }{2} }}

Answer

  • tan = -√5/2
3 0
2 years ago
Given a vector with the initial point, (4,2) and the terminal point, (-3,1), find the vector in unit vector form.
Gwar [14]

Answer:

Wish i can help but i don't understand that

Step-by-step explanation:

7 0
3 years ago
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