1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
photoshop1234 [79]
4 years ago
6

Logan is a land surveyor. He wants to determine d, the distance across a lake that cannot be directly measured. He draws this di

agram to help him.
A right triangle with side length 7 kilometers, d, and hypotenuse of 9 kilometers.

What is the approximate distance across the lake, to the nearest tenth of a kilometer?
A: 5.7 km
B: 6.3 km
C: 11.4 km
D: 16.0 km
Mathematics
2 answers:
sp2606 [1]4 years ago
8 0

Answer:

A

Step-by-step explanation:

xxMikexx [17]4 years ago
5 0

Answer:

a

Step-by-step explanation: amos s_thicc7

You might be interested in
-8 + 3h = 1 <br>i need help its a 2 step equation​
LekaFEV [45]

Answer:

h = 3

Step-by-step explanation:

-8 + 3h = 1

Add 8 to both sides.

3h = 1 + 8

Add 1 and 8 to get 9.

3h = 9

Divide both sides by 3.

h = \frac{9}{3}

Divide 9 by 3 to get 3.

h = 3

7 0
2 years ago
Two trains are moving towards each other. One train moves at a speed of 50 mph, and the other train travels at 60 mph. How soon
Margaret [11]
I think that they will meet in 3 hours and 11 min but I’m not too sure
4 0
3 years ago
Read 2 more answers
A car is on a driveway that is inclined 10 degrees to the horizontal. A force of 490 lb is required to keep the car from rolling
lara31 [8.8K]

Answer:

a) weight  of the car = 2816,1 lbs

b) 2773 lbs

Step-by-step explanation:

The equilibrium force is 490 lbs. That force keep the car at rest, then

∑ Fy  =  0     and  ∑Fx  =  0

Forces acting on the car:

The external force   490 lbs

weight of the car   uknown

Normal force

sin∠10°  =  0,174

cos∠10° = 0.985

∑Fx  =  0         mg*sin10°- 490 = 0      ∑Fy =  0      mg*cos10° - N  =  0

mg*0,174= 490

mg  =  490 / 0,174

mg = 2816,1 lbs

weight  of the car = 2816,1 lbs

The Normal force

mg*cos10° - N  =  0        2816,1 * 0,985 = N

N = 2773 lbs

Then equal force in magnitude and in opposite direction will car exets on the driveway

3 0
3 years ago
Express in the form of p/q :<br><br> (i) 0.12▁3 (ii) 0. ▁621 (iii) 2.2▁18​
konstantin123 [22]

Answer:

1)0.123( bar on 3)

Let X = 0.123 ( bar on 3)

Then X = 0.1233 --------(1)

Multiply equation (1) by 100 we get,

100X = 12.33 --------(2)

Again multiply equation (2) by 10 we get,

1000X = 123.33 -------(3)

Subtract equation (2) from equation (3) we get,

1000X = 123.33

100X = 12.33

____________

900X = 111

X = 111/900

Hence,

0.123 ( bar on 3) is in the form of 111/900 which is in the form of P/Q.

6 0
4 years ago
HELP MEEEE!!!<br><br> which of these graphs do not represent constant rates of change ?
Ganezh [65]

Answer:

Hello! Your answer would be below!

Step-by-step explanation:

Graph B)

Hope I helped! Ask me anything if you have questions!

3 0
3 years ago
Other questions:
  • Write the number 3.8 in the forum of a/b using integers to show that it is a rational number
    6·2 answers
  • Answer quickly and correctly and get a free Brainliest! Solve for k.
    11·2 answers
  • 583,896 word form.what is it pls
    9·1 answer
  • Duo makes 65% of his dumplings with vegetarian fillings. What fraction of Duo's dumplings have vegetarian fillings?
    14·1 answer
  • Lora read 1/8 of a comic book in 2 days she read the same number of pages everyday what part of the book does she read in a week
    10·1 answer
  • Which answer choice shows the equation below written in<br> a different form?<br> 2-5=-3
    12·1 answer
  • Line a: y= x-6<br> Line B = y= 3x+4<br> Which of the following shows the solution
    13·1 answer
  • Please help with this it's urgent!!! Please explain your answer and I will mark brainliest!!!
    8·2 answers
  • NEED HELP ASAP
    14·2 answers
  • Complete the table below: Show all your work.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!