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Marat540 [252]
3 years ago
13

Line a: y= x-6 Line B = y= 3x+4 Which of the following shows the solution

Mathematics
1 answer:
Stells [14]3 years ago
3 0

Answer:

yrnetubtysbutsnydid yiduk

Step-by-step explanation:

nggz jys dynjey ekyneyk dky nutbrykgn hrngdnufk rky duk in ydjeymdeky ydn yje

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8-2w=6w-8 help lol!!!!!!!!!!!
NNADVOKAT [17]
W = 2. How do we find this out?

Put "w" as "2". 8-2(2)=6(2)-8
8 - 4 = 12 - 8.

Solve.

4 = 4

Hope this helps! ☺♥
5 0
3 years ago
Read 2 more answers
A dentist polls his patients and finds that 83 percent brush their teeth at least twice a day, 47 percent floss daily, and 19 pe
puteri [66]

Answer:

The correct option is B. 23%

Step-by-step explanation:

Let the event that patient brushes his teeth at least twice a day is denoted by A

So, P(A) = 0.83

Let the event that patient flosses daily is denoted by B

So, P(B) = 0.47

Now, it is given that 19 percent patients brush at least twice a day and floss daily.

⇒ P(A and B) = 0.19

Now, we need to find conditional probability of occurring event B given A has occurred.

\implies P(B|A) =\frac{P(A\: and\: B)}{P(A)}\\\\\implies P(B|A) = \frac{0.19}{0.83}\\\\\implies P(B|A) = 0.2289\approx 0.23

Hence, Nearest required percentage = 23%

Therefore, The correct option is B. 23%

4 0
3 years ago
Read 2 more answers
What is the graph of the solution to the following compound inequality?
attashe74 [19]

Answer:

A

Step-by-step explanation:

8 0
2 years ago
Questions:
ryzh [129]

Answer:

50 into celsius is 10

45 into fahrenheit is 113

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A recent study examined hearing loss data for 1981 U.S. teenagers. In this sample, 369 were found to have some level of hearing
ruslelena [56]

Answer:

There is no enough evidence to support the claim that the proportion of US teens that have some level of hearing loss differs from 20%.

P-value=0.12

Step-by-step explanation:

We have to perform a test of hypothesis on the proportion.

The claim is that the proportion of US teens that have some level of hearing loss differs from 20%.

Then, the null and alternative hypothesis are:

H_0: \pi=0.20\\\\H_a:\pi\neq0.20

The significance level is assumed to be 0.05.

The sample, of size n=1981, has 369 positive cases. Then, the proportion is:

p=X/n=369/1981=0.186

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.2*0.8}{1981}}=\sqrt{ 0.000081 }= 0.009

Now, we can calculate the statistic z:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.186-0.20+0.5/1981}{0.009}=\dfrac{-0.014}{0.009}=-1.556

The P-value for this two-tailed test is:

P-value=2*P(z

The P-value is below the significance level, so the effect is not significant. The null hypothesis failed to be rejected.

There is no enough evidence to support the claim that the proportion of US teens that have some level of hearing loss differs from 20%.

7 0
3 years ago
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