Question

32 what value of x is the equation 2^2x+ 7 = 2^15true?

Answer 1

Value of x = 7.499

Step-by-step explanation:

We need to find value of x in the equation: $2^{2x}+ 7 = 2^{15}$

This can be solved using natural log

Solving:

$2^{2x}+ 7 = 2^{15}$

Subtract 7 from both sides:

$2^{2x}+ 7-7 = 2^{15}-7$

Simplifying:

$2^{2x}=32768-7$

$2^{2x}=32761$

Using rule if f(x)=g(x) then, ln(f(x))=ln(g(x))

So,

$ln(2^{2x})=ln(32761)$

Applying log rule: logₐ(x^b)= b logₐ(x)

$2x(ln(2))=ln(32761)$

Divide both sides by 2ln(2)

$2x(ln(2))=[tex]\frac{2x(ln(2))}{2(ln(2))}=\frac{ln(32761)}{2(ln(2))} \\x=\frac{ln(32761)}{2(ln(2))}\\Rewriting\,\,32761\,\,as 181^2\\x=\frac{ln(181^2)}{2(ln(2))}\\x=\frac{2ln(181)}{2(ln(2))}\\x=\frac{ln(181)}{ln(2)}\\x=7.499$

So, Value of x = 7.499

Keywords: Solving Equations

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