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BartSMP [9]
3 years ago
5

How many seconds until the ball touches the ground

Mathematics
1 answer:
neonofarm [45]3 years ago
7 0

Answer: 6.06 seconds

Step-by-step explanation:

This will not factor. The ball will hit the ground 6.06 seconds after thrown.

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Which of the following represents the quotient of the polynomial 6x^3+3x^2-5/3x^2+1​
fenix001 [56]

Answer: The quotient is (2x+1)

Step-by-step explanation:

Here, the dividend =  6x^3+3x^2-5

Divisor = (3x^2+1)

By the long division method for finding the quotient we will follow the following steps,

Steps 1 : Write dividend inside the division sign and divisor outside the division sign,

Step 2: Multiply the divisor by 2x and subtract the result by the dividend,

Step 3: Now, again multiply the divisor by 1,

Step 4: Subtract the result by the remaining dividend,

Since, further division is not possible,

Hence, the sum of all terms that are multiplied = 2x+1

Which is our quotient.

4 0
4 years ago
Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
2 years ago
How do you do this question?
r-ruslan [8.4K]

Step-by-step explanation:

y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1

dy/dx = 12√x

Arc length is:

s = ∫ ds

s = ∫₀¹ √(1 + (dy/dx)²) dx

s = ∫₀¹ √(1 + (12√x)²) dx

s = ∫₀¹ √(1 + 144x) dx

If u = 1 + 144x, then du = 144 dx.

s = 1/144 ∫ √u du

s = 1/144 (⅔ u^(³/₂))

s = 1/216 u^(³/₂)

Substitute back:

s = 1/216 (1 + 144x)^(³/₂)

Evaluate between x=0 and x=1.

s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]

s = 1/216 (145)^(³/₂) − 1/216

s = (145√145 − 1) / 216

5 0
3 years ago
Which sign makes this number sentence true?
Karolina [17]

Answer:

its D

Step-by-step explanation:

8 0
3 years ago
What is 1 times 1? Please answer because I need this due in 15 minutes
Sonbull [250]

Answer:

1

Step-by-step explanation:

1*1=1

thats it tbh

8 0
3 years ago
Read 2 more answers
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