Answer: The value of k for which one root of the quadratic equation kx2 - 14x + 8 = 0 is six times the other is k = 3.
Let's look into the solution step by step.
Explanation:
Given: A quadratic equation, kx2 - 14x + 8 = 0
Let the two zeros of the equation be α and β.
According to the given question, if one of the roots is α the other root will be 6α.
Thus, β = 6α
Hence, the two zeros are α and 6α.
We know that for a given quadratic equation ax2 + bx + c = 0
The sum of the zeros is expressed as,
α + β = - b / a
The product of the zeros is expressed as,
αβ = c / a
For the given quadratic equation kx2 - 14x + 8 = 0,
a = k, b = -14, c = 8
The sum of the zeros is:
α + 6α = 14 / k [Since the two zeros are α and 6α]
⇒ 7α = 14 / k
⇒ α = 2 / k --------------- (1)
The product of the zeros is:
⇒ α × 6α = 8 / k [Since the two zeros are α and 6α]
⇒ 6α 2 = 8 / k
⇒ 6 (2 / k)2 = 8 / k [From (1)]
⇒ 6 × (4 / k) = 8
⇒ k = 24 / 8
⇒ k = 3
Answer:
B and C
(I'm not sure if b and e are supposed to be the same though) if they are then, b, c, and e
Answer:
I think what you meant to say is "If a triangle has 2 sides that are 4 cm and 20 cm, what are the possible lengths of the third side?"
Basically, when given 2 sides of a triangle, the third side must be GREATER than the DIFFERENCE of the other 2 sides and LESS than the SUM of the other 2 sides.
difference = 16 cm
sum = 24 cm
So, the third side must be greater than 16 cm and less than 24 cm
Step-by-step explanation:
