Estimate the following sum by rounding each number to the nearest 10plz
1 answer:
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Hello there.
<span>Tyrone mixed 7/12 quart of red paint with 1/12 quart of yellow paint how much paint does Tyrone have in the mixture?
</span><span>
Answer: In this question you need to add together the fractions provided.
The sum would look like this:
</span>
+ 
=
<span>Since the denominators are the same , it is simple to add.
All you need to do is 7 + 1 = 8.
Therefore the end result after solving would look like.
</span> + = 
.
<span>Tyrone has 8/12 quarts of paint.
Hope This Helps You!
Good Luck Studying ^-^</span>
<span>Tyrone mixed 7/12 quart of red paint with 1/12 quart of yellow paint how much paint does Tyrone have in the mixture?
</span><span>
Answer: In this question you need to add together the fractions provided.
The sum would look like this:
</span>
<span>Since the denominators are the same , it is simple to add.
All you need to do is 7 + 1 = 8.
Therefore the end result after solving would look like.
</span>
<span>Tyrone has 8/12 quarts of paint.
Hope This Helps You!
Good Luck Studying ^-^</span>
Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by
The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same
Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by
The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same
Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>