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Molodets [167]
3 years ago
13

Estimate the following sum by rounding each number to the nearest 10plz​

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
7 0

Answer:

184

Step-by-step explanation:

129.5 + 34.62 + 19.1

130 + 35 + 19

184

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En una tienda de ropa vas a comprarte una pantalones que están de 150 a 90 euros y una camiseta de 40 a 24 ¿ tienen el mismo por
uranmaximum [27]

Respuesta:

Sí, tienen el mismo descuento del 40%

Explicación paso a paso:

Dado :

PANTALÓN :

Precio inicial = 150

Precio con descuento = 90

Porcentaje de descuento en el precio:

(150 - 90) / 150 * 100%

60/150 * 100%

0,4 * 100

= 40%

CAMISA:

Precio inicial = 40

Precio con descuento = 24

Porcentaje de descuento en el precio:

(40-24) / 150 * 100%

16/40 * 100%

0,4 * 100

= 40%

Sí, tienen el mismo descuento del 40%

8 0
3 years ago
in the question " Brianna is getting materials for a project. Her teacher gives her a container that has 0.15 L of liquid in it.
devlian [24]
0.15*0.4=0.06
you just multiply it
6 0
3 years ago
Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
soldier1979 [14.2K]

Answer:

a. Outcomes of A = { (C,C,C) , (D,D,D), (S,S,S) }

b. Outcomes of B = { (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }

c. Outcomes of C = { (C,C,C),(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C) }

d. Outcomes of A⋂C = { (C,C,C) }

e. Outcomes of Sample space = { (C,C,C), (C,C,D), (C,C,S), (C,D,C), (C,D,D), (C,D,S), (C,S,C), (C,S,D), (C,S,S), (D,C,C), (D,C,D),(D,C,S), (D,D,C), (D,D,D), (D,D,S), (D,S,C), (D,S,D), (D,S,S),   (S,C,C), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), (S,S,S) }

f. Outcomes of A U B = { (C,C,C) , (D,D,D), (S,S,S), (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }

g. Outcomes of A⋂C^{c} = { (D,D,D), (S,S,S) }

h. Outcomes of A^{c}⋂C = {(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C)}

i. Events A and C are not mutually exclusive

j. Events B and C are mutually exclusive

Step-by-step explanation:

Given - Three times each day, a quality engineer samples a component

             from a recently manufactured batch and tests it. Each part is

             classified as conforming (suitable for its intended use),  

             downgraded (unsuitable for the intended purpose but usable for  

             another purpose), or scrap (not usable). An experiment consists

             of recording the categories of the three parts tested in a particular

              day.

To find - a. Let A be the event that all the parts fall into the same

                  category. List the outcomes in A.

              b. Let B be the event that there is one part in each category.

                  List the outcomes in B.

              c. Let C be the event that at least two parts are conforming.

                  List the outcomes in C.

              d. List the outcomes in A⋂C

              e. List the 27 outcomes in the sample space.

               f. List the outcomes in A U B.

              g. List the outcomes in A⋂C^{c}

              h. List the outcomes in ⋂C.

              i. Are events A and C mutually exclusive? Explain.

              j. Are events B and C mutually exclusive? Explain.

Proof -

Let

Conforming part = C

Downgraded part = D

Scrap part = S

a.)

Given , Let A be the event that all the parts fall into the same category.

Outcomes of A = { (C,C,C) , (D,D,D), (S,S,S) }

b.)

Given, Let B be the event that there is one part in each category.

Outcomes of B = { (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }

c.)

Given,  Let C be the event that at least two parts are conforming.

Outcomes of C = { (C,C,C),(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C) }

d.)

Outcomes of A⋂C = { (C,C,C) }

e.)

Outcomes of Sample space = { (C,C,C), (C,C,D), (C,C,S), (C,D,C), (C,D,D), (C,D,S), (C,S,C), (C,S,D), (C,S,S), (D,C,C), (D,C,D),(D,C,S), (D,D,C), (D,D,D), (D,D,S), (D,S,C), (D,S,D), (D,S,S),   (S,C,C), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), (S,S,S) }

f.)

Outcomes of A U B = { (C,C,C) , (D,D,D), (S,S,S), (C,D,S),(C,S,D),(D,C,S),(D,S,C),(S,C,D),(S,D,C) }

g.)

Outcomes of C^{c}  =  {  (C,D,D), (C,D,S), (C,S,D), (C,S,S), (D,C,D),(D,C,S), (D,D,C), (D,D,D), (D,D,S), (D,S,C), (D,S,D), (D,S,S), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), (S,S,S) }

Outcomes of A⋂C^{c} = { (D,D,D), (S,S,S) }

h.)

Outcomes of A^{c} = {(C,C,D), (C,C,S), (C,D,C), (C,D,D), (C,D,S), (C,S,C), (C,S,D), (C,S,S), (D,C,C), (D,C,D),(D,C,S), (D,D,C),  (D,D,S), (D,S,C), (D,S,D), (D,S,S),   (S,C,C), (S,C,D), (S,C,S), (S,D,C), (S,D,D), (S,D,S), (S,S,C), (S,S,D), }

Outcomes of A^{c}⋂C = {(C,C,D),(C,C,S),(C,D,C),(C,S,C),(D,C,C),(S,C,C) }

i.)

As we two that Two events A and C are mutually exclusive iff A ∩ C = ∅

Now,

A ∩ C = { (C,C,C) }

⇒Events A and C are not mutually exclusive.

j.)

As we two that Two events B and C are mutually exclusive iff B ∩ C = ∅

Now,

B ∩ C = ∅

⇒Events B and C are mutually exclusive.

8 0
3 years ago
Use the given information to bound the p-value of the F statistic for a one-tailed test with the indicated degrees of freedom. F
lianna [129]

Answer:

The range of the <em>p</em>-value is: 0.050 < <em>p</em>-value < 0.100.

Step-by-step explanation:

For checking the equivalence of two population variances of independent samples, we use the <em>f</em>-test.

The test statistic is given by:

F=\frac{S_{1}^{2}}{S_{2}^{2}}\sim F_{\alpha, (n_{1}-1)(n_{2}-1)}

It is provided that the hypothesis test is one-tailed.

The computed value of the test statistic is:

<em>F</em> = 4.23.

The degrees of freedom of the numerator and denominator are:

df_{1}=4\\df_{2}=5

Use MS-Excel to compute the <em>p</em>-value as follows:

Step 1: Select function fX → F.DIST.RT.

Step 2: A dialog box will open. Enter the values of f-statistic and the two degrees of freedom.

*See the attachment below.

Step 3: Press OK.

The <em>p</em>-value is, 0.0728.

The range of the <em>p</em>-value is:

0.050 < <em>p</em>-value < 0.100

4 0
4 years ago
114 students choose to attend one of three after school activities: football, tennis or running. There are 53 boys. 53 students
Masja [62]

Answer:

  1/3

Step-by-step explanation:

The attachment shows a table with the given information filled in. Since we know 53 chose football and 23 chose tennis, the remaining 38 must have chosen running.

Then 38 out of 114 students chose running. The probability that one of those is picked at random is ...

  p(running) = 38/114 = 1/3

5 0
3 years ago
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