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mina [271]
3 years ago
12

if two parrallelograms have the same base length, but the height of the first is half of the second, then what is the ratio of t

he area if the first parrallelogram to that of the second?
Mathematics
1 answer:
Ghella [55]3 years ago
6 0
Area of a parallelogram = b × h
Let the heights of first and second parallelogram be h and h' respectively.
Given that,
h = ½h'
Area of first parallelogram= bh ...(i)
Area of second parallelogram = bh'
but, h = ½h'
Replacing h by ½h' in equation (i)

Therefore, area of first parallelogram = ½bh'

Ratio - ½bh' : bh'
= 1:2
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Helppppppppppppp ASAP
Ivan

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C(n, k)= \frac{n!}{[k!(n-k)!]  }

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6 0
3 years ago
Read 2 more answers
Given: Triangle ABC : triangle ADB. AB =24, AD =16 <br> Find: AC
RoseWind [281]

Answer:

<h2>AC = 36.01</h2>

Step-by-step explanation:

Given ΔABC and ΔADB, since both triangles are right angled triangles then the following are true.

From ΔADB, AB² = AD²+BD²

Given AB = 24 and AD = 16

BD² = AB² - AD²

BD² = 24²-16²

BD² = 576-256

BD² = 320

BD = \sqrt{320}

BD = 17.9

from ΔABC, AC² = AB²+BC²

SInce AC = AD+DC and BC² = BD² + DC² (from ΔBDC )we will have;

(AD+DC)² = AB²+ (BD² + DC²)

Given AD = 16, AB = 24 and BD = 17.9, on substituting

(16+DC)² = 24²+17.9²+ DC²

256+32DC+DC² =  24²+17.9²+ DC²

256+32DC = 24²+17.9²

32DC = 24²+17.9² - 256

32DC = 640.41

DC = \frac{640.41}{32}

DC = 20.01

Remember that AC = AD+DC

AC = 16+20.01

AC = 36.01

6 0
3 years ago
Find mAC<br><br> Help me please
aleksandrvk [35]

Answer:

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Step-by-step explanation:

arc CA is 50 since the angle is 50 and then you would subtract from 180 since it is half the circle which leaves you with C, or 130 degrees.

5 0
3 years ago
If f (x)= x-3 and g (x)= 2x-4, find (f+g)(x)
const2013 [10]

(f∘g)(x) is equivalent to f(g(x)). We solve this problem just as we solve f(x). But since it asks us to find out f(g(x)), in f(x), each time we encounter x, we replace it with g(x).

In the above problem, f(x)=x+3.

Therefore, f(g(x))=g(x)+3.

⇒(f∘g)(x)=2x−7+3

⇒(f∘g)(x)=2x−4

Basically, write the g(x) equation where you see the x in the f(x) equation.

f∘g(x)=(g(x))+3 Replace g(x) with the equation

f∘g(x)=(2x−7)+3

f∘g(x)=2x−7+3 we just took away the parentheses

f∘g(x)=2x−4 Because the −7+3=4

This is it

g∘f(x) would be the other way around

g∘f(x)=2(x+3)−7

now you have to multiply what is inside parentheses by 2 because thats whats directly in front of them.

g∘f(x)=2x+6−7

Next, +6−7=−1

g∘f(x)=2x−1

Its a lts easier than you think!

Hope this helped

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4 years ago
Which two angles are congruent
Anna35 [415]
Angles FED and angle JKL
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