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wolverine [178]
3 years ago
6

What is 10 percent of 2880

Mathematics
2 answers:
Marizza181 [45]3 years ago
8 0
10% of 2880 is equal to 288
Bad White [126]3 years ago
4 0

Answer:

288

Step-by-step explanation:

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How do I set this up
Mrac [35]

To justify the yearly membership, you want to pay at least the same amount as a no-membership purchase, otherwise you would be losing money by purchasing a yearly membership.  So set the no-membership cost equal to the yearly membership cost and solve.

no-membership costs $2 per day for swimming and $5 per day for aerobic, in other words, $7 per day.  So if we let d = number of days, our cost can be calculated by "7d"

a yearly membership costs $200 plus $3 per day, or in other words, "200 + 3d"

Set them equal to each other and solve:


7d = 200 + 3d

4d = 200

d = 50

So you would need to attend the classes for at least 50 days to justify a yearly membership.  I hope that helps!

5 0
2 years ago
Complete the steps to find all zeroes of the function f(x) = x4 − 4x3 − 4x2 + 36x − 45. This function has roots.
xxTIMURxx [149]
Steps?

A graph shows zeros to be ±3. Factoring those out leaves the quadratic
  (x-2)² +1
which has complex roots 2±i.

The function has roots -3, 3, 2-i, 2+i.

7 0
3 years ago
Read 2 more answers
Substitution method need help for home work
Marizza181 [45]
-3y = x...so we sub in -3y for x in the other equation

-x + 7y = 70
-(-3y) + 7y = 70
3y + 7y = 70
10y = 70
y = 70/10
y = 7

so we sub in 7 for y in either of the original equations to find x
-3y = x
-3(7) = x
-21 = x

so ur solution is (-21,7)
6 0
3 years ago
If 32 teams participate in a standard single elimination tournament, how many games must be played to decide a champion?
SCORPION-xisa [38]
<h3>Answer: 31 games</h3>

======================================================

Explanation:

  • 32/2 = 16 games will happen in round 1. Afterward, 16 teams are left.
  • 16/2 = 8 games will happen in round 2. Afterward, 8 teams are left.
  • 8/2 = 4 games happen in round 3.
  • 4/2 = 2 games in round 4.
  • 2/2 = 1 game as the final championship.

Count the number of times you divide by two and we have five occurrences of this. So there five rounds overall.

To get the total number of games played, we add up the quotients

16+8+4+2+1 = 31

----------------

Or as a shortcut we can simply subtract off 1 since 1+2+4+...+2^n = 2^(n+1)-1

We can write that rule as

\displaystyle \sum_{k=1}^{n}2^k = 2^{n+1}-1

which is equivalent to

\displaystyle \sum_{k=1}^{n}2^{k-1} = 2^n-1

3 0
3 years ago
PLEASE ANSWER ASAP! YOUR ANSWER MUST REQUIRE AN EXPLANATION IN ORDER TO RECEIVE 10 POINTS AND THE BRAINLIEST ANSWER!!! THANKS!!!
KIM [24]
Hello,

Using vectors and scalar product:

[(a+c)*\vec{i}+(b-0)*\vec{j} ].[(a-c)*\vec{i}+(b-0)*\vec{j}]=0
Thus
\dfrac{b^2}{(a+c)(a-c)}=1

By the way how can we make text larger in latex \larger{.....} don't work.

Answer A




8 0
3 years ago
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