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Georgia [21]
3 years ago
13

.Complete the pattern: 5,7,4,6,3,5,____

Mathematics
2 answers:
Temka [501]3 years ago
8 0

Answer:

its 2, you add 2 then subtract 3

Step-by-step explanation:

kenny6666 [7]3 years ago
7 0

Answer:

2

Step-by-step explanation:

You add 2 subtract 3

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A triangle and a rectangle are shown below.
nadezda [96]

Answer:

10 cm

Step-by-step explanation:

From the diagram,

Applying,

lw = 5/2(bh)..................... Equation 1

Where l = length of the rectangle, w = width of the rectangle, b = base of the triangle, h = height of the triangle.

make w the subject of the equation

w = 5(bh)/2l............... Equation 2

From the diagram,

Given: l = 12 cm, b = 6 cm, h = 8 cm

Substitute into equation 2

w = 5(6×8)/(2×12)

w = 10 cm

Hence the width of the rectangle is 10 cm

8 0
3 years ago
Select two ratios that are equivant to 7:10
nikdorinn [45]

Answer:

70:100 700:1000 14:20 140:200

7 0
3 years ago
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The statements that are true are A, B, and D
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Martha pays $178 every 4 months for her guitar lessons. At this rate, how much will Martha pay for 3 years of guitar lessons?
TiliK225 [7]
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8 0
3 years ago
What is the inverse and restricted domain of the equation 8x^2-3
kari74 [83]

Answer:  \bold{y=\pm \dfrac{\sqrt{2(x+3)}}{4},\qquad x\neq -3}

<u>Step-by-step explanation:</u>

y = 8x² - 3            (Restriction: none -  x is All Real Numbers)

The inverse is when you swap the x's and y's and then solve for y

x = 8y² - 3            <em>swapped the x and y</em>

x + 3 = 8y²           <em>added 3 to both sides</em>

\dfrac{x+3}{8}=y^2           <em>divided both sides by 8</em>

\sqrt{\dfrac{x+3}{8}}=\sqrt{y^2}           <em>square rooted both sides</em>

\pm \sqrt{\dfrac{x+3}{8}}=y           <em>simplified</em>

\pm \sqrt{\dfrac{x+3}{8}\bigg(\dfrac{2}{2}\bigg)}=y           rationalized the denominator

\pm \sqrt{\dfrac{2(x+3)}{16}}=y           <em>simplified</em>

\pm \dfrac{\sqrt{2(x+3)}}{4}=y           <em>simplified</em>

<u>Restriction:</u>

The radical <em>(inside the square root sign)</em> cannot be negative

→  2(x + 3) ≥ 0

      x + 3 ≥ 0         <em>divided both sides by 2</em>

      x       ≥ -3         <em>subtracted 3 from both sides</em>



4 0
3 years ago
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