Distance<-------------300--------------><-------------------x----------------->
⊕---------------------------------⊕--------------------------------------⊕ Express Freight Overtaking point
Speed 55 speed 30
Let x be the distance travelled by Freight until the point of overtaking
Time = Distance/Speed, then:
Time (freight) = Distance (fright)/Speed (freight) And
Time (Express) = Distance (Express)/Speed (Express).
Now plug in the relative number:
Time (freight) = x/30 and Time (express) = (x+300)/55. But note that both times are equal, then:
x/30 = (x+300)/55 OR (x÷30 = (x+300)÷55) [Answer C]
Now let's find the distance x. Cross multiplication;
55x= 30(300+x) →55x = 9,000 + 30x
55x - 30x = 9,000 → 25x = 9,000 and x = 9,000/25 = 360 miles
Time needed for Freight to travel 360 m = 360/30= 12 Hours
Time needed for Express to travel (300+360) m = 660/55= 12 Hours
As you see, it's the same time of 12 hours
Don't forget that Distance = Speed x time or time = Distance/Speed, etc.
6 * 2.5 = 15 That’s the area of the base
2.5 * 4 = 10
10 * 2 = 20
That’s the area of the 2 smaller sides
6 * 4 = 24
24 * 2 = 48
That’s the area of the 2 larger sides
Then you add all the dimensions together.
15+20+48 = 83.
So, the final equation is (6*2.5) + 2(2.5*4) + 2(6*4) = 83
Hey, I think an image is needed to answer this question.
Answer:
Median = 13
Step-by-step explanation:
We are given the following data:
16, 15, 13, 12, 17, 14, 11, 9, 11
Formula:
Sorted data: 9, 11, 11, 12, 13, 14, 15, 16, 17
Median =
Thus, the median of the given data is 13.
Answer:
10
Step-by-step explanation:
