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2 years ago

Ques

Mathematics

1 answer:

natulia [17]2 years ago

6 0

Answer:

Step-by-step explanation:

In a Pythagorean triple the square on the longest side is equal to the sum of the squares on the other 2 sides.

longest side = 10 ⇒ 10² = 100

6² + 8² = 36 + 64 = 100

A is a Pythagorean triple

longest side = 17 ⇒ 17² = 289

8² + 15² = 64 + 225 = 289

B is a Pythagorean triple

longest side = 9 ⇒ 9² = 81

5² + 8² = 25 + 64 = 89

89 ≠ 81

C is not a Pythagorean triple

longest side = 13 ⇒ 13² = 169

5² + 12² = 25 + 144 = 169

D is a Pythagorean triple

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the volume of the rectangular prism shown below is 96 cubic feet. The dimensions of the prism base are 4 feet and 3 feet. What i

g100num [7]

Height=volume:base area
96:(4*3)= 96:12=8

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2 years ago

Vignesh owns a cottage in the shape of a cube with each edge of length 26 feet. The roof is in the shape of a square pyramid and

Zina [86]

Answer:

56√93 ≈ 540 ft²

Step-by-step explanation:

The roof is made up of 4 congruent isosceles triangles. Since the roof extends 2 ft over the edge of the cottage on each side, then the base of each triangle is 26 + 2 = 28 ft.

Let's calculate the area of one of the triangles and then just multiply by 4. See attachment. Drop a perpendicular from the vertex of a triangle to its base. We now have the triangle broken up into two right triangles. The hypotenuse is 17 ft and one of the legs of the right triangle is 28 / 2 = 14 ft. Then the height / other leg is:

$\sqrt{17^2-14^2} =\sqrt{289-196} =\sqrt{93}$

We now have the dimensions of each triangle: the height is √93 and the base is 28. The area of a triangle is: A = (1/2) * b * h, so we have the following.

A = (1/2) * b * h

A = (1/2) * 28 * √93 = 14√93

Multiply this by 4:

14√93 * 4 = 56√93

The total surface area is 56√93 ≈ 540 ft².

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2 years ago

Read 2 more answers

The vertices of triangle PQR are P(10,-6), Q(6,2), & R(4,-1). Describe a translation that places the image of the triangle e

Gnoma [55]

Answer:

Translate 7 units up and then translate 11 units to the left.

Step-by-step explanation:

We have the triangle PQR having co-ordinates (10,6), (6,2) and (4,-1).

It is required to translate ΔPQR so that the resulting image is completely inside the 2nd quadrant.

So, for that we will apply the following sequence of translations:

1. Translate 7 units up.

This will give us the figure in the 1st quadrant having co-ordinates (10,1), (6,9) and (4,6).

2. Translate 11 units to the left

We will get the final triangle P'Q'R' with the co-ordinates P'(-1,1), Q'(-5,9) and R'(-7,6) as shown below.

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3 years ago

find the coordinates of the point P on the parabola y=1-x^2 with domain 0≤x≤1 that minimize the area of the triangle enclosed by

coldgirl [10]

Let point P be with coordinates $(x_0,y_0).$ Find the equation of the tangent line.

1. If $y=1-x^2,$ then $y'=-2x.$

2. The equation of the tangent line at point P is

$y-y_0=-2x_0(x-x_0).$

Find x-intercept and y-intercept of this line:

when x=0, then $y=y_0+2x_0^2;$
when y=0, then $x=\dfrac{y_0}{2x_0}+x_0=\dfrac{y_0+2x_0^2}{2x_0}.$

The area of the triangle enclosed by the tangent line at P, the x-axis, and y-axis is

$A=\dfrac{1}{2}\cdot (2x_0^2+y_0)\cdot \left(\dfrac{y_0+2x_0^2}{2x_0}\right)=\dfrac{(y_0+2x_0^2)^2}{4x_0}.$

Since point P is on the parabola, then $y_0=1-x_0^2$ and

$A=\dfrac{(1-x_0^2+2x_0^2)^2}{4x_0}=\dfrac{(1+x_0^2)^2}{4x_0}.$

Find the derivative A':

$A'=\dfrac{2(1+x_0^2)\cdot 2x_0\cdot 4x_0-4(1+x_0^2)^2}{16x_0^2}=\dfrac{12x_0^4+8x_0^2-4}{16x_0^2}.$

Equate this derivative to 0, then

$12x_0^4+8x_0^2-4=0,\\ \\3x_0^4+2x_0^2-1=0,\\ \\D=2^2-4\cdot 3\cdot (-1)=16,\ \sqrt{D}=4,\\ \\x_0^2_{1,2}=\dfrac{-2\pm4}{6}=-1,\dfrac{1}{3},\\ \\x_0^2=\dfrac{1}{3}\Rightarrow x_0_{1,2}=\pm\dfrac{1}{\sqrt{3}}.$