The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.
Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11
Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
Answer:
2
Step-by-step explanation:
-13 x 2 = -26
-4 x 2 = -8
14 x 2 = 28
-26 + -8 + 28 +-9 = -15
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Answer:
21:27 and 14:18
Step-by-step explanation:
We can solve this by using common factors
one of the common factors of 54 and 42 is 3
42/3=14
54/3=18
so one of the ratios is 14:18
another common factor is 2
42/2=21
54/2=27
so another ratio is 21:27